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aniked [119]
3 years ago
12

I need help I don’t understand

Mathematics
1 answer:
makkiz [27]3 years ago
5 0

Answer: not much help i can barley see the paper

Step-by-step explanation:

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Find the product <br> -1/2 y(2y3-8)
MissTica
0-(( \frac{1}{2} *y)*2y^3-8) \\ \\ then \ we \ would \ simplify \ 1/2 \\ \\ we \ factor y^3 - 4 \\ \\ 4 \ would \ not \ be \ a \ perfect \ cube. \\ \\ therefore, \ your \ answer \ would \ then \ be \ the \ following: \\ \\ \boxed{ -y * (y^3 - 4)}
8 0
3 years ago
I need help with this question.
Papessa [141]

Answer:

It's A, c =2.5d

Step-by-step explanation:

When it comes to problems like this, I usually look through the answers and try to plug in the numbers until I get the right equation that fits with the graph.

2.5(5) = 12.5

2.5(10)= 25

2.5(15)= 37.5

2.5(20) = 50

2.5(25) = 62.5

If you compare this to the graph, you'll notice the solutions are the same as the Total Cost (c). That's because c= 2.5d is the right equation for this graph. (Sorry if my explanation is confusing)

5 0
2 years ago
Suppose a is jointly proportional to b and c. if a=4 when b=8 and c = 9, then what is a when b=2 and c=18
asambeis [7]

From the given information, a exists jointly proportional to b and c.

then $$a \propto b c$

Therefore, the value of a exists 2.

<h3>What is the value of a?</h3>

Given, a exists jointly proportional to b and c.

$$a \propto b c$

Taking K as the constant of proportionality.

a = K b c

For b = 8 and c = 9, the value of a = 4

4 = K(8)(9)

4 = 72 K

Dividing the equation by 72, we get

$K=\frac{1}{18}

Using the value of K in the equation:

$a=\frac{b c}{18}

Substitute the values of b = 2 and c = 18, in the above equation

$a=\frac{2 \times 18}{18} \\

a = 2

Therefore, the value of a exists 2.

To learn more the value of x refers to:

brainly.com/question/11874663

#SPJ4

6 0
11 months ago
If y varies directly with x, and y is 12 when x is 8, find y when x is 9.​
jasenka [17]

Answer:

26

Step-by-step explanation:

its not

5 0
2 years ago
PLEASE HURRY :,) WILL GIVE BRAINLEST
Vlad1618 [11]

Answer:

Point R is at (-40,30),  a distance of 60 units from point Q

Step-by-step explanation:

<u>Explanation </u>

<u>we will use below conditions</u>

<u>Type of transformation</u>                                 <u> change to co-ordinate point</u>

  1. vertical translation up 'd' units                (x, y) changes to (x, y +d)
  2. vertical translation down 'd' units            (x, y) changes to (x, y-d)
  3. horizontal translation left 'c' units            (x, y)  changes to (x- c, y)  

   4. horizontal translation right 'c' units         (x, y) changes to (x+ c , y)

now Given data is P( 20,-30) and in the graph Q(-40,-30)

Step1:-

<u>Now we have to find 'R' point</u>

Given data the point "R' is vertically above point Q so the point "Q' is moves vertically up with '60' units

now we will use the condition (1)

Q(-40,-30) is <u>vertical translation up '60' units </u>now changes the co-ordinate point is (-40 , -30+60)

<u>The correct translation and The point R( -40 , 30)</u>

<u>Step2:-</u>

Again in the given data  "R" is at the same distance from point Q as point P is from point Q.

<u>so given P point is (20 , -30)</u>

now we translation 'P' also

<u>vertically translation up at a distance '60' units</u> and changes the new co-ordinate (20 , -30+60) that is (20,30)  [ use above condition  is (1)]

and again<u> horizontal translation left '60</u>' now changes (20 - 60 ,30)[ use condition (3)]

There fore the new co-ordinate is R( -40 , 30)

<u>Final answer:-</u>

Point R is at (−40, 30), a distance of 60 units from point Q

6 0
3 years ago
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