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Alborosie
3 years ago
12

Use this system of linear equations to solve for x. 3x+5y=6 and 2x+y=4​

Mathematics
2 answers:
Oduvanchick [21]3 years ago
8 0

Answer:

x=2

HPT 3x+5y=6 (1) và 2x+y=4 (2)

Nhân phương trình (2) với 5 để hệ số y của 2 phương trình bằng nhau. Ta có:

(2)⇔ 10x+5y=20(3)

Trừ (3) cho (1), có: 7x+0y=14⇒x=2

svp [43]3 years ago
4 0

Answer:

3x+5y=6.....eqn 1

2x+y=4.......eqn 2

y=4-2x.....eqn 3

Step-by-step explanation:

substitute eqn 3 into eqn 1

3x+5(4-2x)=6

3x+20-10x=6

-7x = -14

x=2

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GIVING BRAINLIEST Green Middle School has 270 boys, 250 girls, 26 teachers, and a supporting staff of 5 employees. The school us
salantis [7]

Answer:

b 119,600

Step-by-step explanation:

250+270+26+5=551 250+270 = 520 520/551 ~94%

94% of 126,776~ 119,600

8 0
3 years ago
The author believes we are “endangering our health by not using the metric system.” Do you agree or disagree and why?
crimeas [40]
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If we were using some other units this may not be the case. For example, british and american inch were different until 1950's.

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3 years ago
I will MARK CROWN just need help
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Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Suppose 4/5 of a different box of oranges weighs 8 pounds how many pounds of oranges are in the full box​
romanna [79]

Answer:

10

Step-by-step explanation:

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8 0
3 years ago
Help with numer 5 please. thank you​
Alex17521 [72]

Answer:

See Below.

Step-by-step explanation:

We are given that:

\displaystyle I = I_0 e^{-kt}

Where <em>I₀</em> and <em>k</em> are constants.

And we want to prove that:

\displaystyle \frac{dI}{dt}+kI=0

From the original equation, take the derivative of both sides with respect to <em>t</em>. Hence:

\displaystyle \frac{d}{dt}\left[I\right] = \frac{d}{dt}\left[I_0e^{-kt}\right]

Differentiate. Since <em>I₀ </em>is a constant:

\displaystyle \frac{dI}{dt} = I_0\left(\frac{d}{dt}\left[ e^{-kt}\right]\right)

Using the chain rule:

\displaystyle \frac{dI}{dt} = I_0\left(-ke^{-kt}\right)  = -kI_0e^{-kt}

We have:

\displaystyle \frac{dI}{dt}+kI=0

Substitute:

\displaystyle \left(-kI_0e^{-kt}\right) + k\left(I_0e^{-kt}\right) = 0

Distribute and simplify:

\displaystyle -kI_0e^{-kt} + kI_0e^{-kt} = 0 \stackrel{\checkmark}{=}0

Hence proven.

4 0
3 years ago
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