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zlopas [31]
3 years ago
12

The author believes we are “endangering our health by not using the metric system.” Do you agree or disagree and why?

Mathematics
1 answer:
crimeas [40]3 years ago
8 0
I agree with the author. By using the metric system we know the exact amount of a medicine we took, whether it's in mg or mL. This way every doctor can prescribe the same amount.
If we were using some other units this may not be the case. For example, british and american inch were different until 1950's.

Example: if you go to a surgery and a doctor needs to cut "1 inch from the left part" it may cause a mistake as this unit is different in different countries. But if he needs to cut "2.5 cm from the left part" he knows exactly where to cut.

Another benefit of using metric system is that it is being used in almost every country in the world.
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Akeem has 24 meters of rope.Which of the following lengths is equal to 24 meters? A 0.024 kilometers b 0.24 kilometers c 2.4 kil
Vsevolod [243]
1 meter = 0.001 kilometers

So 24 * 0.001 = 0.024

24 meters = 0.024 kilometers
8 0
3 years ago
PLEASE HELP!!!
Simora [160]
1)
y = ax+b

6 = 3a + b
18 = 5a + b

b = 6 - 3a
18 = 5a + 6 - 3a

2a = 12
a = 6
b = 6 - 18
b = -12

f(x) = 6x -12

2)
y = 2 
No, because y ≠ 4

x = 2 
No, because it's vertical<span>
</span>
y = 4 
Yes, because x ∈ <span>ℝ and y = 4
</span>
x = 4
No, because it's verical


7 0
4 years ago
Ocean sunfishes are well-known for rapidly gaining a lot of weight on a diet based on jellyfish. The relationship between the el
ki77a [65]

Answer:

1.4071

Step-by-step explanation:

The relationship between the elapsed time, t in days, since an ocean sunfish is born, and its mass is given by:

M_{day}(t)=3.5(1.05)^t

This function represents an exponential growth increasing as the number of days increases since (3.5 > 1), it means that at day 0 , the mass of the sunfish is 3.5 milligrams and every day, its mass increases by a factor of 1.05.

Since the mass of the sunfish increases by 1.05^t, therefore the mass of the sunfish increases every one week (that is 7 days) by a factor of 1.05^{7} = 1.4071

8 0
3 years ago
What is the volume of a hemisphere with a radius of 5.7 m, rounded to the nearest
Sindrei [870]

Answer: 387.9 m

Step-by-step explanation:

Volume of a Sphere:

V=\frac{4}{3}\pi r^3

V=

3

4

​

πr

3

\text{radius} = 5.7

radius=5.7

meters

\text{Plug in:}

Plug in:

\frac{4}{3}\pi (5.7)^3

3

4

​

π(5.7)

3

775.734624395

775.734624395

Use calculator

\text{Volume of Hemisphere HALF of Volume of Sphere:}

Volume of Hemisphere HALF of Volume of Sphere:

\frac{775.734624395}{2}

2

775.734624395

​

Divide volume by 2

387.867312198

387.867312198

\approx 387.9\text{ m}^3

≈387.9 m

3

6 0
3 years ago
An aircraft manufacturer wants to determine the best selling price for a new airplane. The company estimates that the initial co
Blizzard [7]

Answer:

(a) C(x)=500+20x-5x^{\frac{3}{4}}+0.01x^2

    p(x)=320-7.7p

    R(x)=(320-7.7p)p=320p-7.7p^2

(b) x=82 \text{planes}

(c) p=\$30.91 M\;\; \text{per plane}

(d) maximum profit =\$ 15.90M

Step-by-step explanation:

Given that,

The company estimates that the initial cost of designing the aeroplane and setting up the factories in which to build it will be 500 million dollars.

The additional cost of manufacturing each plane can be modelled by the function.

m(x)=20x-5x^{\frac{3}{4}}+0.01x^2

(a)  Find the cost, demand (or price), and revenue functions.

   C(x)=500+20x-5x^{\frac{3}{4}}+0.01x^2

   p(x)=320-7.7p

   R(x)=(320-7.7p)p=320p-7.7p^2

(b)  Find the production level that maximizes profit.

    f=R(x)-C(x)

 \Rightarrow f=320p-7.7p^2-(500+20x-5x^{\frac{3}{4}}+0.01x^2)

\Rightarrow df=320dp-15.4pdp-20dx+5(\frac{3}{4} )x^{\frac{-1}{4} }dx-0.02xdx

     x=320-7.7p

     p=\frac{320-x}{7.7}

    \frac{dp}{dx} = \frac{-1}{7.7}

\frac{df}{dx}=\frac{320}{-7.7} -\frac{15.4(320-x) }{7.7(\frac{-1}{7.7} )}-20+5\frac{3}{4} x^{\frac{-1}{4}} -0.02x=0

    \Rightarrow -41.5584+83.1169-0.2597x-20+3.75x^{\frac{-1}{4} }-0.02x=0

   \Rightarrow 21.5585+3.75x^{\frac{-1}{4} }-0.279x=0

   \Rightarrow x=82 \text{planes}

(c)  Find the associated selling price of the aircraft that maximizes profit.

  p=\frac{320-82}{7.7}

\Rightarrow p=\$30.91 M\;\; \text{per plane}

(d)  Find the maximum profit.

Manufacturing cost of one plane is:

m(1)=20-5+0.01

         =\$15.01 M

maximum profit =\$(30.91-15.01)M

                           =\$15.90M

3 0
3 years ago
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