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2 years ago

I REALLY NEED HELP!!!

Mathematics

2 answers:

Kipish [7]2 years ago

8 0

Answer:

complementary

Step-by-step explanation:

The angles are part of a right angle as shown by the square.

Complementary angles are angles that add up to 90˚

since x-15 and 2x are parts of the right angle, they add up to 90

Allushta [10]2 years ago

3 0

Answer:

Complementary angles

Step-by-step explanation:

Complementary angles are angles that add up to 90 degrees.

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A 2 digit square whose digits add up to an even number

NeX [460]

8^2 is 64, and 6+4=10 which is even

5 0

3 years ago

Simplify completely (x^2+x-12)/(x^2-x-20)÷(3x^2-24+45)/(12x^2-48x-60)

likoan [24]

To simplify the expression, we can check if there are terms that are needed to be added or subtracted. In this case, there are none. We get the factors of 4 equations present in the expression.
x^2+x-12 = {3,-4}
x^2-x-20 = {5,-4}
3x^2-24+45 = {5,3}
12x^2-48x-60 = {5,-1}

hence we cancel 5 and from numerator and denominator.

the answer is (x+4)^2/ (x-5)*(x+1)

6 0

3 years ago

How to do part a & b

nata0808 [166]

You can do part a using The Pythagoras theorem:-

30^2 = x^2 + 24^2

x^2 = 30^2 - 14^2 = (30+24)(30-24) = 324

x = 18

7 0

3 years ago

Read 2 more answers

Use the data in the table to estimate f’’(1.5)

Ne4ueva [31]

Answer:

Do you still need help?

Step-by-step explanation:

6 0

2 years ago

Test the four possible vertices that you found in the objective function in part A. Use those values to determine which set of v

irga5000 [103]

The testing of the four vertices of the objective function gives;

C(5, 0, 55) = 430

C(5, 30, 25) = 400

C(15, 30, 15) = 420

C(45, 0, 15) = 510 (maximum)

<h3>How to test objective functions?</h3>

The objective function is seen as attached.

Now, it is noticed that just two of the vertices are listed. The other two vertices are intersections of x + y + z = 60 with x = 5 and the constraints on y.

We will assume that; 0 ≤ y ≤ 30

Thus, the missing vertices are;

(x, y, z) = (5, 0, 55) and (5, 30, 25)

The two given vertices are;

(x, y, z) = (15, 30, 15) and (45, 0, 15)

Therefore, the objective function values are;

C(5, 0, 55) = 9·5 +6·0 +7·55 = 45 +0 +385 = 430

C(5, 30, 25) = 9·5 +6·30 +7·25 = 45 +180 +175 = 400

C(15, 30, 15) = 9·15 +6·30 +7·15 = 135 +180 +105 = 420

C(45, 0, 15) = 9·45 +6·0 +7·15 = 405 +0 +105 = 510

Read more about Objective Functions at; brainly.com/question/16826001

#SPJ1

5 0

1 year ago