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Lynna [10]
3 years ago
14

In a function, y varies inversely with x. The consistent of variation is 4. Which table could represent the function?

Mathematics
1 answer:
lianna [129]3 years ago
5 0

Answer:

none of the tables shown

Step-by-step explanation:

Inverse variation is

xy = k where k is the constant

xy = 4

in the top table

-2*2 = -4 so it cannot be the first table

In the middle table

-2 * -8 = 16  so it is not the middle table

In the bottom table

-2 *4 = -8 so it is not the bottom table

There must be a table not shown

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Answer:

Step-by-step explanation:

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prisoha [69]

Answer:


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Solve the initial value problem: y'(x)=(4y(x)+25)^(1/2) ,y(1)=6. you can't really tell, but the '1/2' is the exponent
goblinko [34]

Answer:

y(x)=x^2+5x

Step-by-step explanation:

Given: y'=\sqrt{4y+25}

Initial value: y(1)=6

Let y'=\dfrac{dy}{dx}

\dfrac{dy}{dx}=\sqrt{4y+25}

Variable separable

\dfrac{dy}{\sqrt{4y+25}}=dx

Integrate both sides

\int \dfrac{dy}{\sqrt{4y+25}}=\int dx

\sqrt{4y+25}=2x+C

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Put C into equation

Solution:

\sqrt{4y+25}=2x+5

or

4y+25=(2x+5)^2

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Hence, The solution is y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4} or y(x)=x^2+5x

4 0
3 years ago
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Answer:

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Step-by-step explanation:

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