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Aleks [24]
3 years ago
5

A function ,f, is defined by the set {(2,3), (4,7), (-1,5)}. if f is reflected in the line y=x, which point will be in the refle

ction?
a. (5,-1) b. (-5,1) c. (1,-5) d. (-1,5)
Mathematics
1 answer:
kotykmax [81]3 years ago
6 0

Answer:

the answer is d

Step-by-step explanation:

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Write in decimal form:4 x 100 +2 x 10+4 X 1 +7 (1/10) +7 x (1/100) +0 x (1/1000)
Helga [31]

This number is written in extended form. Each multiplication determines the place the digit is in the number you have to determine.

4*100 → This indicates that the first digit of the number is in the place of the "hundreds", if you solve the multiplication the result is 400

2*10 → This multiplication indicates that the second digit of the number is in the place of the "tens", the result of the multiplication is 20

4*1 → This multiplication indicartes that the third digit of the number represents the "units", te result of the multiplication is 4

After the units you have to put the decimal point and all digits below it will be decimal values.

7*(1/10) → The first digit after the decimal point is in the "tenths" place, you can write it as 0.7

7*(1/100) → This indicates that this digit is in the second place after the decimal dot, in the "hundredths" place, you can write it as 0.07

0*(1/1000)→ The multiplication indicates that the digit is in the third place after the decimal dot, in the "thousands" place, you can write it as 0.000

To write the number in decimal form you have to put each digit in their given order, or add the result of each multiplicatin toghether:

400+20+4+0.7+0.07+0.000

424.770

7 0
1 year ago
let x1,x2, and x3 be linearly independent vectors in R^(n) and let y1=x2+x1; y2=x3+x2; y3=x3+x1. are y1,y2,and y3 linearly indep
Nutka1998 [239]

Answer with Step-by-step explanation:

We are given that

x_1,x_2 and x_3 are linearly independent.

By definition of linear independent there exits three scalar a_1,a_2 and a_3 such that

a_1x_1+a_2x_2+a_3x_3=0

Where a_1=a_2=a_3=0

y_1=x_2+x_1,y_2=x_3+x_2,y_3=x_3+x_1

We have to prove that y_1,y_2 and y_3 are linearly independent.

Let b_1,b_2 and b_3 such that

b_1y_1+b_2y_2+b_3y_3=0

b_1(x_2+x_1)+b_2(x_3+x_2)+b_3(x_3+x_1)=0

b_1x_2+b_1x_1+b_2x_3+b_2x_2+b_3x_3+b_3x_1=0

(b_1+b_3)x_1+(b_2+b_1)x_2+(b_2+b_3)x_3=0

b_1+b_3=0

b_1=-b_3...(1)

b_1+b_2=0

b_1=-b_2..(2)

b_2+b_3=0

b_2=-b_3..(3)

Because x_1,x_2 and x_3 are linearly independent.

From equation (1) and (3)

b_1=b_2...(4)

Adding equation (2) and (4)

2b_1==0

b_1=0

From equation (1) and (2)

b_3=0,b_2=0,b_3=0

Hence, y_1,y_2 and y_3 area linearly independent.

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3 years ago
Write the property that matches the equation.<br> 3+(4+7)=(3+4)+7
miss Akunina [59]

Answer:

associative property

Step-by-step explanation:

3 0
3 years ago
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Is (0, 0) a solution to the equation y = x?
Mandarinka [93]

Answer:

yes

Step-by-step explanation:

if both y and x are 0 than it is true that they equal each other since 0=0

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4 years ago
Find the slope of a line that passes through points (-2,1) and<br> (3,-5)
klasskru [66]

Answer:

-1.2

Step-by-step explanation:

4 0
3 years ago
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