Answer:17
Step-by-step explanation:
Lets split this into two parts; a semi circle and triangle. We can solve fro the area of both individually first.
Area of the Semi Circle:
Formula: A = (πr²)/2
The radius is the diameter divided by two (16 / 2 = 8)
A = (π*8²)/2
A = (π64)/2
A = 200.96/2
A = 100.48 meters
The area of the semi circle is 100.48 meters
Area of the Triangle:
Formula: A = bh/2
A = 16*12/2
A = 192/2
A = 96 meters
The area of the triangle is 96 meters.
To find the total area of the shape, we can add.
100.48 + 96 = 196.48 meters.
Best of Luck!
Truncated . . . 28.45 . / / / Rounded . . . 28.46 .
Answer:
The numerical limits for a B grade is between 81 and 89.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

B: Scores below the top 13% and above the bottom 56%
Below the top 13%:
Below the 100-13 = 87th percentile. So below the value of X when Z has a pvalue of 0.87. So below X when Z = 1.127. So




Above the bottom 56:
Above the 56th percentile, so above the value of X when Z has a pvalue of 0.56. So above X when Z = 0.15. So




The numerical limits for a B grade is between 81 and 89.
Answer:
10
Step-by-step explanation:
Pythagorus thereom. So
8sq +6sq= xsq
64+36=100
Sq root 100 is 10