Is there a picture I can see
Http://prntscr.com/anjh06
The image I saw was a paper with 90° edges. the 90° was cut into 2, 75° and x.
x = 90° - 75° = 15°
Interior angles of a triangle should equal 180°. The other corner of the paper is part of the triangle. It has a measure of 90°
The two angles are 15° and 90°. To find the remaining unknown angle, we deduct the two angles from 180°
3rd angle = 180° - 15° - 90°
3rd angle = 180° - 105°
3rd angle = 75°
1st term = -10
2nd term = -6
3rd term = -2
4th term = 2
5th term = 6
6th term = 10
7th term = 14
The reason how I got 14 for the 7th term is because, i added 4 to each term.
Hope this helps!
To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.
jk=ac and j+k=b
The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...
2k^2-5k-18=0
2k^2+4k-9k-18=0
2k(k+2)-9(k+2)=0
(2k-9)(k+2)=0
so k=-2 and 9/2
k=(-2, 4.5)
