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miss Akunina [59]

3 years ago

11

Bob bought an investment at $550 and sold it at $723. What was his

2 answers:

Shalnov [3]3 years ago

7 0

The correct answe would be C...

Dahasolnce [82]3 years ago

3 0

Yea it would be C :)

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Gina's literacy bucket weighs 6 pounds. Her novel weighs 1 4/6 pounds, and her chrome book weighs 2 1/6 how much would her bucke

Paraphin [41]

Answer:

$2\frac{1}{6}$ pounds.

Step-by-step explanation:

We have been given that Gina's literacy bucket weighs 6 pounds. Her novel weighs 1 4/6 pounds, and her chrome book weighs 2 1/6.

To find weight of bucket after taking out the two items, we will subtract weight of each item from 6 pounds as:

$\text{Weight of bucket}=6-1\frac{4}{6}-2\frac{1}{6}$

Let us convert mixed fractions into improper fractions as:

$1\frac{4}{6}=\frac{6\cdot 1+4}{6}=\frac{10}{6}\\\\2\frac{1}{6}=\frac{6\cdot 2+1}{6}=\frac{12+1}{6}=\frac{13}{6}$

$\text{Weight of bucket}=6-\frac{10}{6}-\frac{13}{6}$

$\text{Weight of bucket}=\frac{6\cdot 6}{6}-\frac{10}{6}-\frac{13}{6}$

$\text{Weight of bucket}=\frac{36}{6}-\frac{10}{6}-\frac{13}{6}$

Combine numerators:

$\text{Weight of bucket}=\frac{36-10-13}{6}$

$\text{Weight of bucket}=\frac{13}{6}$

$\text{Weight of bucket}=2\frac{1}{6}$

Therefore, the weight of the bucket is $2\frac{1}{6}$ pounds.

6 0

3 years ago

I need to get all of them solved by tomorrow, and I have no idea where to start with any of them

Tems11 [23]

Answer:

1- x=4,3

2- x= 2, 5/6

3- x= i dont know

4- b-

c-

d- $2x\frac{3}{2}$

6 0

3 years ago

Solve for k:<br> 310 – (30 x 7) = 5 x k

tester [92]

Answer:

k=20

Step-by-step explanation:

ph*tomath (the app) is your friend btw because this would be really easy to solve using that but

solve for k:

simplify the left side as 310-210 then =100

so 100=5k

divide by 5 and k=20

7 0

3 years ago

Isabelle and her parents plan to share the cost of her college education. The annual tuition cost for the college she plans to a

oksano4ka [1.4K]

Answer:

7392

Step-by-step explanation:

just divide 5544÷.75 on a calculator however you want to do it than you will get 7392

5 0

3 years ago

The average value of a function f over the interval [−2,3] is −6 , and the average value of f over the interval [3,5] is 20. Wha

Xelga [282]

Answer:

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

Step-by-step explanation:

Let suppose that function $f$ is continuous and integrable in the given intervals, by integral definition of average we have that:

$\frac{1}{3-(-2)} \int\limits^{3}_{-2} {f(x)} \, dx = -6$ (1)

$\frac{1}{5-3} \int\limits^{5}_{3} {f(x)} \, dx = 20$ (2)

By Fundamental Theorems of Calculus we expand both expressions:

$\frac{F(3)-F(-2)}{3-(-2)} = -6$

$F(3) - F(-2) = -30$ (1b)

$\frac{F(5)-F(3)}{5-3} = 20$

$F(5) - F(3) = 40$ (2b)

We obtain the average value of $f$ over the interval $[-2, 5]$ by algebraic handling:

$F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)$

$F(5) - F(-2) = 10$

$\frac{F(5)-F(-2)}{5-(-2)} = \frac{10}{5-(-2)}$

$\bar f = \frac{10}{7}$

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

4 0

2 years ago