Answer:
Concurrent as my perception
V=(4/3)(pi)(r^3)
r=7
Hope this’ll help
Answer:
Tina's average speed for the whole journey = 56 kmph
Step-by-step explanation:
Time taken by Sean to travel from Town A to Town B = 4 hours.
Average speed of Sean = 70 km/h
We have equation of motion, s = ut + 0.5 at²
Time, t = 4 hours.
Initial speed, u = 70 km/hr
Acceleration, a = 0 m/s²
Substituting
s = ut + 0.5 at²
s = 70 x 4 + 0.5 x 0 x 4²
s = 280 km
Distance from Town A to Town B = 280 km
Tina took 1 hour more than Sean.
Time taken by Tina to travel from Town A to Town B = 4 +1 = 5 hours
We have equation of motion, s = ut + 0.5 at²
Time, t = 5 hours.
Displacement, s = 280 km
Acceleration, a = 0 m/s²
Substituting
s = ut + 0.5 at²
280 = u x 5 + 0.5 x 0 x 5²
u = 56 km/hr
Tina's average speed for the whole journey = 56 kmph
Answer:
The heaviest 5% of fruits weigh more than 747.81 grams.
Step-by-step explanation:
We are given that a particular fruit's weights are normally distributed, with a mean of 733 grams and a standard deviation of 9 grams.
Let X = <u><em>weights of the fruits</em></u>
The z-score probability distribution for the normal distribution is given by;
Z =
~ N(0,1)
where,
= population mean weight = 733 grams
= standard deviation = 9 grams
Now, we have to find that heaviest 5% of fruits weigh more than how many grams, that means;
P(X > x) = 0.05 {where x is the required weight}
P(
>
) = 0.05
P(Z >
) = 0.05
In the z table the critical value of z that represents the top 5% of the area is given as 1.645, that means;



x = 747.81 grams
Hence, the heaviest 5% of fruits weigh more than 747.81 grams.
between 3 and 4 would be 3.5cm