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katrin2010 [14]
3 years ago
15

Andrew bought 5 identical packages of dried fruit the total weight of the packages is 1.25 pounds what is the weight of each pac

kage?
Mathematics
1 answer:
mina [271]3 years ago
5 0
0.25. Tell me in comments if you need an explanation
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D/5=4 A.d=20 B.d=4/5 C.d=5/4​
ludmilkaskok [199]
It would be A/ 20 since 20/5 will be 4
5 0
3 years ago
Liam has 12 red balloons and 14 blue balloons.He put all of his balloons in 2 equal groups. How many balloons are in each group?
Law Incorporation [45]

Answer:

A.13

Step-by-step explanation:

You just have to add the 12 and the 14 and then divide it by 2.

12+14=26

26/2=<em> 13 </em>

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<em>Hope it helps!</em>

4 0
3 years ago
Read 2 more answers
Which could be the entire interval over which the function,
saveliy_v [14]

Answer:

(-2,1)

Step-by-step explanation:

The bracket is an opened interval

zero is neutral either positive or Negative

so the range of values in (-2,1) is -1,0 with corresponding values 2 each

hence, they're positive

8 0
3 years ago
Read 2 more answers
Compute the multifactor productivity measure for each of the weeks shown for production of chocolate bars. What do the productiv
liq [111]

Answer:

Week 1 =3.03

Week 2 =2.99

Week 3=2.9

Week 4=2.83

Step-by-step explanation:

Computation for the multifactor productivity measure for each of the weeks shown for production of chocolate bars.

Using this formula

Week Multifactor productivity measure = (Output / Total Cost)

Where:

Output represent Quantity produced

Total cost represent Labor cost + Material cost + Overhead

Let plug in the formula

Week 1= 30,000/(40*12*6)+[(40*12*6)1.5]+(450*6)

Week 1 =30,000/(2,880)+(2,880*1.5)+2,700

Week 1 =30,000/(2,880+4,320+2,700)

Week 1=30,000/9,900

Week 1 =3.03

Week 2= 33,600/(40*12*7)+[(40*12*7)1.5]+(470*6)

Week 2 =33,600/(3,360)+(3,360*1.5)+2,820

Week 2=33,600/(3,360+5,040+2,820)

Week 2=33,600/11,220

Week 2 =2.99

Week 3= 32,200/(40*12*7)+[(40*12*7)1.5]+(460*6)

Week 3 =32,200/(3,360)+(3,360*1.5)+2,760

Week 3=32,200/(3,360+5,040+2,760)

Week 3=32,200/11,160

Week 3=2.9

Week 4= 35,400/(40*12*8)+[(40*12*8)1.5]+(480*6)

Week 4 =35,400/(3,840)+(3,840*1.5)+2,880

Week 4=35,400/(3,840+5,760+2,880)

Week 4=35,400/12,480

Week 4=2.83

Therefore the multifactor productivity measure for each of the weeks shown for production of chocolate bars is :

Week 1 =3.03

Week 2 =2.99

Week 3=2.9

Week 4=2.83

4 0
3 years ago
Solve for -5/6*n=40<br><br> 56<br><br> 48<br><br> -48<br><br> -56
oee [108]

Solve for -5/6*n=40

n = 40/(-5/6)

n = 40 * -6/5

n = -48

answer n= -48

5 0
3 years ago
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