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Lemur [1.5K]
3 years ago
9

Please help me I will give you the brain thing with extra points if you help me, please. I need to get this right. 1/5

Mathematics
2 answers:
GarryVolchara [31]3 years ago
6 0
A! Reflection across Y axis! Good luck hope this helps!
denpristay [2]3 years ago
4 0

Answer:

It is a reflection over the y-axis

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What is 16/80 simplified?
Temka [501]
The answer will be 1/5

3 0
3 years ago
Read 2 more answers
Someone please help me answer this!!
PolarNik [594]
0.000518
just add 4 zeros to the left of the number
6 0
3 years ago
Your dog eats 7/8 lb of food in 4 meals , how many meals will it take your dog to eat 1 lb of food
blondinia [14]

Answer:

The dog needs eat 4.6 meals

Step-by-step explanation:

Due to:

7/8 lb ----> 4 meals

1 lb --------> X meals

X = [(1 lb)*(4 meals)] / [7/8 meals]

X = 4.6 meals

Best regards

4 0
3 years ago
Will give brainliest!!! The MTC Theater holds 250 people, and last night’s performance sold out! Students under the age of 16 pa
MakcuM [25]
60 children tickets and 190 adult tickets were sold.

Step-by-step explanation:

Let the no. of adult tickets sold be 'a'

Let the no. of children tickets sold be 'c'

Total tickets sold = 250

Cost of 1 children ticket = $2.5

Cost of 1 adult ticket = $4

Total money collected= $910

Given that,
a + c = 250
a = 250 - c
4a + 2.5c = 910

Substitute a value
4(250 - c) + 2.5c = 910
1000 - 4c + 2.5c = 910
1000 - 1.5c = 910
-1. 5c = -90
1.5c = 90
c = 90/1.5
c = 60
a + c = 250
a + 60 = 250
a = 190
4 0
2 years ago
A luxury liner leaves a port on a bearing of 110 degrees and travels 8.8 miles. It then turns due west and travels 2.4 miles. Ho
myrzilka [38]

Answer:

Distance= 6.6 miles

Bearing= N 62.854°W

Step-by-step explanation:

Let's determine angle b first

Angle b=20° (alternate angles)

Using cosine rule

Let the distance between the liner and the port be x

X² =8.8²+2.4²-2(8.8)(2.4)cos20

X²= 77.44 + 5.76-(39.69)

X²= 43.51

X= √43.51

X= 6.596

X= 6.6 miles

Let's determine the angles within the triangle using sine rule

2.4/sin b = 6.6/sin20

(2.4*sin20)/6.6= sin b

0.1244 = sin b

7.146= b°

Angle c= 180-20-7.146

Angle c= 152.854°

For the bearing

110+7.146= 117.146

180-117.146= 62.854°

Bearing= N 62.854°W

8 0
3 years ago
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