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Dennis_Churaev [7]
3 years ago
6

A restaurant records the number of tables served each night, and the results have the values: minimum = 3, lower

Mathematics
2 answers:
natulia [17]3 years ago
6 0

Answer: A. The first one

Step-by-step explanation:

Triss [41]3 years ago
3 0
<h2><u><em>A </em></u></h2>

I got an 100%

Please Give me Brainliest

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50= -2.5x<br> can someone help me solve this? thank you!
Katarina [22]

Answer: x=-20

Step-by-step explanation:

Isolate the variable(x) by dividing each side by factors (50) that do not contain the variable.

6 0
3 years ago
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Given the following mAB = mBC= mCD in circle F what is the measure of angle AFB
Svetach [21]
50° <span>is the measure of angle AFB</span>

8 0
3 years ago
1. perpendicular to x - 6y = 2; (2, 4)
nordsb [41]

Answer:

all work is pictured and shown

7 0
3 years ago
An investor invested a total of $2,800 in two mutual funds. One fund earned 5% profit while the other earned 3% profit. If the i
Natasha_Volkova [10]

Answer:

The amount invested in the mutual fund that earned 5% was $1,000

The amount invested in the mutual fund that earned 3% was $1,800

Step-by-step explanation:

Let

x ----> the amount invested in the mutual fund that earned 5%

y ----> the amount invested in the mutual fund that earned 3%

we know that

x+y=2,800 ----> y=2,800-x ----> equation A

5\%=5/100=0.05

3\%=3/100=0.03

0.05x+0.03y=104 ----> equation B

Solve the system by substitution

substitute equation A in equation B

0.05x+0.03(2,800-x)=104

Solve for x

0.05x+84-0.03x=104

0.05x-0.03x=104-84

0.02x=20

x=\$1,000

<em>Find the value of y</em>

y=2,800-x

y=2,800-1,000=\$1,800

therefore

The amount invested in the mutual fund that earned 5% was $1,000 and the amount invested in the mutual fund that earned 3% was $1,800

5 0
3 years ago
Solve for x in the equation x2-8x+41=0
alex41 [277]
X = [-(-8) +/- sqrt((-8)^2 -4*41)] / 2  

x =  ( 8 + sqrt (-100) / 2  and  (8 - sqrt(-100) / 2

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4 0
4 years ago
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