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3 years ago

A bag contains 6 red balls and 5 black balls . Two balls are picked , one after the other . Find the probability that :

Mathematics

1 answer:

Kaylis [27]3 years ago

7 0

Answer:

<u>There are:</u>

6 red balls - R
5 black balls - B
Total number = 11 balls

<h3>A. Without replacement</h3>

i. <u>Two blacks </u>

P(BB) = 5/11*4/10 = 2/11

ii. <u>The first is black</u>

P(B) = 5/11

or, alternatively

P(BR or BB) = 5/11*6/10 + 2/11 = 3/11 + 2/11 = 5/11

iii. <u>Both are of same colour</u>

P(BB or RR) = 2/11 + 6/11*5/10 = 2/11 + 3/11 = 5/11

<h3>B. With replacement</h3>

i. <u>Two blacks </u>

P(BB) = 5/11*5/11 = 25/121

ii. <u>The first is black</u>

P(B) = 5/11

or alternatively

P(BR or BB) = 5/11*6/11 + 25/121 = 30/121 + 25/121 = 55/121 = 5/11

iii. <u>Both are of same colour</u>

P(BB or RR) = 5/11*5/11 + 6/11*6/11 = 25/121 + 36/121 = 61/121

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Step-by-step explanation:

Step 1: Simplify both sides of the equation.

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Step 2: Add 2x to both sides.

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here is a link:

https://www.mathpapa.com/algebra-calculator.html?q=6-4x%3D6x-8x-2.

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