Answer:
Step-by-step explanation:
the right choice is C
you use c^2=a^2+b^2
where the largest side is the hypotenuse
The number in the ones place= X
The number in the tenths place= y
y+x=14.
y=14-x
Original placement of numbers=10y+x
New placement of numbers(after subtraction of 36)= 10x+y
10y+ x-36=10x+y
Substitute y with 14-x
So we would get
10(14-x)+ x-36=10x+(14-x)
=140-10x+x-36=10x+14-x
After transposing we get
140-14-36=10x-x+10x-x
=90=18x
X=90/18
x=5
Y=14-x
=14-5
=9
So the two digit number is
10y+x
=90+5
=95
I am pretty sure the answer is D, but I'm not 100% sure
Answer:
7/20
Step-by-step explanation:
