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Fiesta28 [93]
4 years ago
15

Find four solutions to the equation (x^2-9)(x^4-16)=0

Mathematics
1 answer:
Zanzabum4 years ago
6 0
The answwer is 

x=-2 x=2 or x=-3 x=3
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PLEASE HELP!! its due in 20 minutes and i dont get this
Goryan [66]

Answer:

Please see below :)

Step-by-step explanation:

The slope is just what's in front of the x!

So:

1.) slope = -1/4

2.) slope = undefined

3.) slope = -9

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7 0
3 years ago
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Triangle ABC has vertices A(- 3, - 4), B(16, - 2) and C(13, - 10) . Show algebraically that ABC is a right angled triangle.​
8_murik_8 [283]

Given:

The vertices of a triangle ABC are A(-3,-4), B(16,-2) and C(13,-10).

To show:

That the triangle ABC is a right angled triangle.​

Solution:

Distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

The vertices of a triangle ABC are A(-3,-4), B(16,-2) and C(13,-10).

Using the distance formula, we get

AB=\sqrt{(16-(-3))^2+(-2-(-4))^2}

AB=\sqrt{(19)^2+(2)^2}

AB=\sqrt{361+4}

AB=\sqrt{365}

Similarly,

BC=\sqrt{\left(13-16\right)^2+\left(-10-\left(-2\right)\right)^2}

BC=\sqrt{73}

And,

AC=\sqrt{\left(13-\left(-3\right)\right)^2+\left(-10-\left(-4\right)\right)^2}

AC=\sqrt{292}

Now, add the square of two smaller sides.

BC^2+AC^2=(\sqrt{73})^2+(\sqrt{292})^2

BC^2+AC^2=73+292

BC^2+AC^2=365

BC^2+AC^2=(AB)^2

Since the sum of the square of two smaller sides is equal to the square of the largest side, therefore the given triangle is a right angle triangle by using Pythagoras theorem.

Hence proved.

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myrzilka [38]
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A similarity transformation maps polygon ABCD to polygon PQRS. If the length of is 6 and the length of the corresponding side, ,
Oduvanchick [21]
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1/2

factor is 1/2
8 0
3 years ago
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Pleaseee help! i need the answer for x (look at picture)
Semenov [28]

Answer:

180 - 133

Step-by-step explanation:

4 0
3 years ago
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