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photoshop1234 [79]
3 years ago
14

A body having uniform velocity has zero acceleration. Give reason.​

Physics
2 answers:
Law Incorporation [45]3 years ago
6 0

Answer:

Acceleration defines change of velocity of a body in a unit time interval. It measures how much velocity is changing in a given time interval. If the body has uniform velocity, it means velocity is not changing. So the change in velocity is zero. In other words, its acceleration is zero.

Explanation:

Acceleration roughly means “change in velocity.” If this change in velocity is consistently in one direction, the body will reach a point at which its velocity is zero. Another consideration is when you drop a basketball onto the pavement. The ball falls, hits the ground, and comes back up. Because its direction of motion changed, you know that its velocity MUST have been 0 m/s at some point during the bounce. This doesn't mean there was no acceleration at this point. Let's suppose that the object has no acceleration when its velocity is zero. The ball would fall, strike the ground, and stick to it like superglue. Obviously, the ball doesn't behave in this fashion. Instead, the ball rises shortly after hitting the ground, which means the acceleration due to the force applied by the ground increases as the ball is squished into the ground until it is greater than the acceleration due to gravity. At this point, the ball starts slowing down, until it stops—but the upward acceleration still exists. Thus, the ball quickly rises immediately after it becomes stationary and bounces off the ground. Another example is when you're in a car, stopped at a red light. When it turns green, you accelerate; however, because you started stationary, there MUST be a point at which your velocity was zero and your acceleration was nonzero. If acceleration had to be zero when the velocity of the car is zero, the car wouldn't be able to move—ever. And, as many others have stated, a vertically fired projectile still has an acceleration of-9.81 m/s² due to gravity at the highest point of its flight. If it did not, it would not turn around and fall to the earth. It would just hover in the sky indefinitely, which would actually be kinda cool.

Nimfa-mama [501]3 years ago
4 0

Answer:

A body having uniform velocity has zero acceleration because there is no change in velocity. hope it helps you.

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when the driver of a car applies the brakes a force of 4000N brings the car to a stop over a distance of 50m.calculate the work
Dimas [21]

Answer:

W = F*d

W = 4000*50

W = 200000J

W = 200KJ

4 0
3 years ago
Two identical charged pith balls are brought together to touch each other. They are then
sergejj [24]

Answer:

-17.5 nC

Explanation:

charge A = -30 nC

charge B = -5 nC

After adding them it would be the average of the two charges because of the getting same voltage difference. so

c = (-30+(-5)) / 2 nC

c= -17.5 nC

answer is -17.5 nC

4 0
3 years ago
You charge a parallel-plate capacitor, remove it from the battery, and prevent the wires connected to the plates from touching e
Degger [83]

Answer:

i) C decreases

ii) Q remains constant

iii) E remains constant

iv) ΔV increases

Explanation:

i)

We know, capacitance is given by:

C=\frac{\epsilon_0.A}{d}

\therefore C\propto \frac{1}{d}

<em>In this case as the distance between the plates increases the capacitance decreases while area and permittivity of free space remains constant.</em>

ii)

As the amount of charge has nothing to do with the plate separation in case of an open circuit hence the charge Q remains constant.

iii)

Electric field between the plates is given as:

E=\frac{\sigma}{\epsilon_0}

where:

charge density, \sigma=\frac{Q}{A}

<em>As we know that distance of plate separation cannot affect area of the plate. Charge Q and permittivity are also not affected by it, so E remains constant.</em>

iv)

  • From the basic definition of voltage we know that it is the work done per unit charge to move it through a distance.
  • Here we increase the distance so the work done per unit charge increases.
6 0
3 years ago
A cannonball with a mass of 8.3 kg is fired from a cannon that has a mass of 949.3 kg. The cannonball is fired with a speed of 1
Fittoniya [83]
<span>conservation of momentum
mass(ball) × speed(ball) = mass(cannon) × speed(cannon)
(8.3 kg) × (187.9 m/s) = (949.3 kg) × v
1.64 m/s = v
</span>
6 0
3 years ago
Suppose that in a lightning flash the potential difference between a cloud and the ground is 1.3×109 V and the quantity of charg
Georgia [21]

Answer:

A) ΔU = 3.9 × 10^(10) J

B) v = 8420.75 m/s

Explanation:

We are given;

Potential Difference; V = 1.3 × 10^(9) V

Charge; Q = 30 C

A) Formula for change in energy of transferred charge is given as;

ΔU = QV

Plugging in the relevant values gives;

ΔU = 30 × 1.3 × 10^(9)

ΔU = 3.9 × 10^(10) J

B) We are told that this energy gotten above is used to accelerate a 1100 kg car from rest.

This means that the initial potential energy will be equal to the final kinetic energy since all the potential energy will be converted to kinetic energy.

Thus;

P.E = K.E

ΔU = ½mv²

Where v is final velocity.

Plugging in the relevant values;

3.9 × 10^(10) = ½ × 1100 × v²

v² = [7.8 × 10^(8)]/11

v² = 70909090.9090909

v = √70909090.9090909

v = 8420.75 m/s

4 0
3 years ago
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