Solve the system of equations using elimination 2x+y=3 and 3x-y=12

1 answer:

3 0

2x + y = 3
3x - y = 12
Add both equations
5x = 15, x = 3
2(3) + y = 3
6 + y = 3, y = -3
Solution: x = 3, y = -3... or (3,-3)

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Lori bought some cookies for $2 each and muffins for $3 each. She bought twice as

Lubov Fominskaja [6]

Answer:

2 cookies

Step-by-step explanation:

let c represent cookies, m represent muffins. set up a system of equations:

2c+3m=16

m=2c

(the top equation shows that cookies are $2 each, and muffins are $3, and that the total cost is $16. the bottom equation shows that Lori bought twice as many muffins as cookies).

then solve the system of equations by substitution, substituting 2c for m in the top equation:

2c+3(2c)=16

2c+6c=16

8c=16

c=2

this means that lori bought 2 cookies.

7 0

2 years ago

Read 2 more answers

Can u help me ASAP. i need to know how to do it step by step

12345 [234]

Answer:

Step-by-step explanation:

$f(x) =4x^3-8x^2+ax+b$ has a factor $2x-1$ and

when divided by $x+2$ , remainder is 20.

To find:Remainder when divided by (x-1) ?

Solution:

$2x-1$ is a factor

$2x - 1 = 0 \Rightarrow x = \frac{1}{2}$ when we put this value of x to the function, it will become 0.

i.e.

$\Rightarrow f(\dfrac{1}{2}) =0 =4\times (\dfrac{1}2)^3-8(\dfrac{1}2)^2+\dfrac{a}{2}+b=0\\\Rightarrow \dfrac{1}{2}-2+\dfrac{a}{2}+b=0\\\Rightarrow 1-4+a+2b=0\\\Rightarrow a +2b=3 ......(1)$