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Kay [80]
3 years ago
15

19. Suppose 3 marbles are drawn without replacement from a bag containing 3 yellow and 4 white marbles. (a) Draw a histogram for

the number of yellow marbles in the sample. (b) What is the expected number of yellow marbles in the sample?

Mathematics
1 answer:
Alina [70]3 years ago
7 0

Answer:

(a) see attachment

(b) E(x) = 226/105

Step-by-step explanation: see attachment

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What does Csc²x equal to?<br><br> A- 1<br><br> B- 1 + sec²x<br><br> C- 1 / sin²x<br><br> D- 1-cos x
Lorico [155]

Answer:

C - 1 / sin^2x

Step-by-step explanation:

as csc x = 1 / sin x

so, csc^2 x = 1 / sin^ 2x

4 0
3 years ago
Prove the following
fomenos

Answer:

Step-by-step explanation:

\large\underline{\sf{Solution-}}

<h2 /><h2><u>Consider</u></h2>

\rm \: \cos \bigg( \dfrac{3\pi}{2} + x \bigg) \cos \: (2\pi + x) \bigg \{ \cot \bigg( \dfrac{3\pi}{2} - x \bigg) + cot(2\pi + x) \bigg \}cos(23π+x)cos(2π+x)

<h2><u>W</u><u>e</u><u> </u><u>K</u><u>n</u><u>o</u><u>w</u><u>,</u></h2>

\rm \: \cos \bigg( \dfrac{3\pi}{2} + x \bigg) = sinx

\rm \: {cos \: (2\pi + x) }

\rm \: \cot \bigg( \dfrac{3\pi}{2} - x \bigg) \: = \: tanx

\rm \: cot(2\pi + x) \: = \: cotx

So, on substituting all these values, we get

\rm \: = \: sinx \: cosx \: (tanx \: + \: cotx)

\rm \: = \: sinx \: cosx \: \bigg(\dfrac{sinx}{cosx} + \dfrac{cosx}{sinx}

\rm \: = \: sinx \: cosx \: \bigg(\dfrac{ {sin}^{2}x + {cos}^{2}x}{cosx \: sinx}

\rm \: = \: 1=1

<h2>Hence,</h2>

\boxed{\tt{ \cos \bigg( \frac{3\pi}{2} + x \bigg) \cos \: (2\pi + x) \bigg \{ \cot \bigg( \frac{3\pi}{2} - x \bigg) + cot(2\pi + x) \bigg \} = 1}}

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

<h2>ADDITIONAL INFORMATION :-</h2>

Sign of Trigonometric ratios in Quadrants

  • sin (90°-θ)  =  cos θ
  • cos (90°-θ)  =  sin θ
  • tan (90°-θ)  =  cot θ
  • csc (90°-θ)  =  sec θ
  • sec (90°-θ)  =  csc θ
  • cot (90°-θ)  =  tan θ
  • sin (90°+θ)  =  cos θ
  • cos (90°+θ)  =  -sin θ
  • tan (90°+θ)  =  -cot θ
  • csc (90°+θ)  =  sec θ
  • sec (90°+θ)  =  -csc θ
  • cot (90°+θ)  =  -tan θ
  • sin (180°-θ)  =  sin θ
  • cos (180°-θ)  =  -cos θ
  • tan (180°-θ)  =  -tan θ
  • csc (180°-θ)  =  csc θ
  • sec (180°-θ)  =  -sec θ
  • cot (180°-θ)  =  -cot θ
  • sin (180°+θ)  =  -sin θ
  • cos (180°+θ)  =  -cos θ
  • tan (180°+θ)  =  tan θ
  • csc (180°+θ)  =  -csc θ
  • sec (180°+θ)  =  -sec θ
  • cot (180°+θ)  =  cot θ
  • sin (270°-θ)  =  -cos θ
  • cos (270°-θ)  =  -sin θ
  • tan (270°-θ)  =  cot θ
  • csc (270°-θ)  =  -sec θ
  • sec (270°-θ)  =  -csc θ
  • cot (270°-θ)  =  tan θ
  • sin (270°+θ)  =  -cos θ
  • cos (270°+θ)  =  sin θ
  • tan (270°+θ)  =  -cot θ
  • csc (270°+θ)  =  -sec θ
  • sec (270°+θ)  =  cos θ
  • cot (270°+θ)  =  -tan θ
7 0
3 years ago
Read 2 more answers
Clarissa went to her favorite restaurant for dinner. if her meal cost 12.00 and she wants to add a 15 %tip how much is her total
Natalija [7]
12.00*0.15=1.80
12+1.80=13.80
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3 0
3 years ago
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Find the arc length and area of a sector with radius R =60 inches and central angle equals 30° round your answer to the nearest
Black_prince [1.1K]

Answer:

(a)31.42 inches

(b)942.48 Square Inches

Step-by-step explanation:

Given a sector of a circle with the following dimensions:

Radius of the circle =60 inches

Central Angle of the sector =30°

(a)Arc Length

Arc Length =\dfrac{\theta}{360^\circ}X2\pi r

=\dfrac{30}{360^\circ}X2*60*\pi\\\\=10\pi\\\\=31.42$ Inches (correct to the nearest hundredth)

(b)Area of the sector

Area of the sector =\dfrac{\theta}{360^\circ}X\pi r^2

=\dfrac{30}{360^\circ}X\pi*60^2\\\\=300\pi\\\\=942.48$ Square Inches (correct to the nearest hundredth)

3 0
3 years ago
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The cost per minute for a conference phone call originally 2.60 increased by 30% what is the new price?
harkovskaia [24]
c.) $3.38

Original price = $2.60 
* It is the basis of increase thus, 100%
* 
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To get the new price, simply multiply the original price to 130%

$2.60 * 130% = $3.38

Another way of solving the problem is getting the equivalent of 30% and adding it to the original price.

$2.60 * 30% = $0.78
$2.60 + $0.78 = $3.38

6 0
3 years ago
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