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Kay [80]
3 years ago
15

19. Suppose 3 marbles are drawn without replacement from a bag containing 3 yellow and 4 white marbles. (a) Draw a histogram for

the number of yellow marbles in the sample. (b) What is the expected number of yellow marbles in the sample?

Mathematics
1 answer:
Alina [70]3 years ago
7 0

Answer:

(a) see attachment

(b) E(x) = 226/105

Step-by-step explanation: see attachment

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$60 is the answer to this question
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Solve for X<br> Solve for X
sammy [17]
X = 9

Work:
5x-3+48+90=180 (sum)
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3 0
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In New York City at the spring equinox there are 12 hours 8 minutes of daylight. The
slamgirl [31]

Answer:

  independent: day number; dependent: hours of daylight

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  1.79 fewer hours on Feb 10

Step-by-step explanation:

a) The independent variable is the day number of the year (t), and the dependent variable is daylight hours (d).

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b) The average value of the sinusoidal function for daylight hours is given as 12 hours, 8 minutes, about 12.133 hours. The amplitude of the function is given as 2 hours 53 minutes, about 2.883 hours. Without too much error, we can assume the year length is 365.25 days, so that is the period of the function,

March 21 is day 80 of the year, so that will be the horizontal offset of the function. Putting these values into the form ...

  d(t) = (average value) +(amplitude)sin(2π/(period)·(t -offset days))

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c) d(41) = 10.34, so February 10 will have ...

  12.13 -10.34 = 1.79

hours less daylight.

5 0
3 years ago
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Tpy6a [65]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
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nikdorinn [45]
So hmmm notice the picture below

"x" being how many seconds the object was going

and when y = 0, the object hits the ground, either on the moon or on earth

so, if we set y = 0 on each equation, we'll know when that happen, how long of a "x-value" or seconds it took

\bf \begin{array}{llll}&#10;\textit{on the moon}\\\\&#10;h=-2.7t^2+96t\implies 0=t(96-2.7t)&#10;\end{array} \quad &#10;\begin{cases}&#10;0=t\\&#10;-------\\&#10;0=96-2.7t\\&#10;2.7t=96\\&#10;t=\frac{96}{2.7}\\&#10;t\approx 35.\overline{55}&#10;\end{cases}\\\\&#10;-------------------------------\\\\&#10;\begin{array}{llll}&#10;\textit{on earth}\\\\&#10;h=-16t^2+96t\implies 0=t(96-16t)&#10;\end{array} \quad &#10;\begin{cases}&#10;0=t\\&#10;------\\&#10;0=96-16t\\&#10;16t=96\\&#10;t=\frac{96}{16}\\&#10;t=6&#10;\end{cases}

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3 years ago
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