Answer:
C - 1 / sin^2x
Step-by-step explanation:
as csc x = 1 / sin x
so, csc^2 x = 1 / sin^ 2x
Answer:
Step-by-step explanation:

<h2 /><h2>
<u>Consider</u></h2>

<h2>
<u>W</u><u>e</u><u> </u><u>K</u><u>n</u><u>o</u><u>w</u><u>,</u></h2>




So, on substituting all these values, we get




<h2>Hence,</h2>

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬
<h2>ADDITIONAL INFORMATION :-</h2>
Sign of Trigonometric ratios in Quadrants
- sin (90°-θ) = cos θ
- cos (90°-θ) = sin θ
- tan (90°-θ) = cot θ
- csc (90°-θ) = sec θ
- sec (90°-θ) = csc θ
- cot (90°-θ) = tan θ
- sin (90°+θ) = cos θ
- cos (90°+θ) = -sin θ
- tan (90°+θ) = -cot θ
- csc (90°+θ) = sec θ
- sec (90°+θ) = -csc θ
- cot (90°+θ) = -tan θ
- sin (180°-θ) = sin θ
- cos (180°-θ) = -cos θ
- tan (180°-θ) = -tan θ
- csc (180°-θ) = csc θ
- sec (180°-θ) = -sec θ
- cot (180°-θ) = -cot θ
- sin (180°+θ) = -sin θ
- cos (180°+θ) = -cos θ
- tan (180°+θ) = tan θ
- csc (180°+θ) = -csc θ
- sec (180°+θ) = -sec θ
- cot (180°+θ) = cot θ
- sin (270°-θ) = -cos θ
- cos (270°-θ) = -sin θ
- tan (270°-θ) = cot θ
- csc (270°-θ) = -sec θ
- sec (270°-θ) = -csc θ
- cot (270°-θ) = tan θ
- sin (270°+θ) = -cos θ
- cos (270°+θ) = sin θ
- tan (270°+θ) = -cot θ
- csc (270°+θ) = -sec θ
- sec (270°+θ) = cos θ
- cot (270°+θ) = -tan θ
Answer:
(a)31.42 inches
(b)942.48 Square Inches
Step-by-step explanation:
Given a sector of a circle with the following dimensions:
Radius of the circle =60 inches
Central Angle of the sector =30°
(a)Arc Length
Arc Length 

(b)Area of the sector
Area of the sector 

c.) $3.38
Original price = $2.60
* It is the basis of increase thus, 100%
* The increase is 30%, thus, 100% + 30% = 130%
To get the new price, simply multiply the original price to 130%
$2.60 * 130% = $3.38
Another way of solving the problem is getting the equivalent of 30% and adding it to the original price.
$2.60 * 30% = $0.78
$2.60 + $0.78 = $3.38