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Oduvanchick [21]
3 years ago
6

32.6 × 10

x^{2}" alt="x^{2} x^{2} \\x^{2}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
borishaifa [10]3 years ago
4 0

Answer:

A plants grow form a ?

Seed

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If f(x) = sqrt of x-3, which inequality can be used to find the domain of f(x)?
LenKa [72]

Answer:

x - 3 ≥ 0

Step-by-step explanation:

The given function is f(x) = \sqrt{x-3}

Here we need to find the inequality that is used to find the domain of the function.

We should not have negative number inside the square root because if negative number comes inside the square root, then it is not a function.

Therefore, (x - 3) must be greater than or equal to 0

That is x - 3 ≥ 0

We use the above inequality to find the domain of the function.

When we solve the above inequality, we get the domain of the function.

x - 3≥0

add 3 on both sides, we get

x - 3 + 3 ≥ 0 + 3

x ≥ 3

Domain is the set of all real numbers greater than or equal 3.

Therefore,  the answer to the question is x - 3 ≥ 0

3 0
3 years ago
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A man is standing on the bridge about to bungee jumps he weighs 54 kg the bridge is 67 meters high
olga nikolaevna [1]
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5 0
3 years ago
What is 490% written as a decimal?
Bingel [31]
If we first convert it to a fraction, we get 490/100. Now if we actually do 490 ÷ 100, we get 4.9, which is the answer. I hope this helps!
5 0
3 years ago
Suppose that x has a binomial distribution with n = 201 and p = 0.45. (Round np and n(1-p) answers to 2 decimal places. Round yo
ycow [4]

Answer:

a) It can be used because np and n(1-p) are both greater than 5.

Step-by-step explanation:

Binomial distribution and approximation to the normal:

The binomial distribution has two parameters:

n, which is the number of trials.

p, which is the probability of a success on a single trial.

If np and n(1-p) are both greater than 5, the normal approximation to the binomial can appropriately be used.

In this question:

n = 201, p = 0.45

So, lets verify the conditions:

np = 201*0.45 = 90.45 > 5

n(1-p) = 201*(1-0.45) = 201*0.55 = 110.55 > 5

Since both np and n(1-p) are greater than 5, the approximation can be used.

3 0
3 years ago
Can someone plz solve this for me??
erma4kov [3.2K]
I think it’s 67 but I’m not sure
7 0
3 years ago
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