1/8 m = 6
m = 48. Hope it helps! :) If you could vote my answer as the brainiest, that would be awesome! :)
Answer:
whats the question? i'm not sure what you're trying to ask here
Step-by-step explanation:
It’s 42 but Carrier the 2
Answer: 
Step-by-step explanation:
If you took the nth root of x, it is the same as raising x to the power of 1/n. Therefore:
![\sqrt[7]{x^{2} } = (x^{2} )^{1/7} = (x^{\frac{2}{7}})\\\sqrt[5]{x^{3} } = (x^{3} )^{1/5} = (x^{\frac{3}{5}})](https://tex.z-dn.net/?f=%5Csqrt%5B7%5D%7Bx%5E%7B2%7D%20%7D%20%20%3D%20%28x%5E%7B2%7D%20%29%5E%7B1%2F7%7D%20%3D%20%28x%5E%7B%5Cfrac%7B2%7D%7B7%7D%7D%29%5C%5C%5Csqrt%5B5%5D%7Bx%5E%7B3%7D%20%7D%20%20%3D%20%28x%5E%7B3%7D%20%29%5E%7B1%2F5%7D%20%3D%20%28x%5E%7B%5Cfrac%7B3%7D%7B5%7D%7D%29)
And multiply:

Answer: 11
=========================
Explanation:
To find the inverse, or f^-1 of a function, you first replace the y= 6x-4 with x=6y-4
Finding the inverse from here is basically just finding y in terms of x.
1) x=6y-4
2) x+4=6
3) (x+4)/6= y
y= (x+4)/6 is now your f^-1.
Now that you have your inverse, replace 62 with your x in y=(x+4)/6
1) (62+4)/6
2) 66/6
3) 11
Therefore, f^-1(62)= 11
Hope this helps :)