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lorasvet [3.4K]
3 years ago
14

Please help me find the solution ​

Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
8 0
C.) (-4,3)
Use the process of elimination and plug in the answer of x or y to one of the problems

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A manufacturing plant earned $80 per man hour of labor when it opened. Each year, the plant earns an additional 5% per man hour.
Mekhanik [1.2K]

Answer:

The amount that plant earns per man hour after (t) years it open is           $80 (1.05)^{\textrm t} .

Step-by-step explanation:

Given as :

The earning of  manufacturing plant when it opened = $ 80 per man hour

The rate of plant earning per man hour  = 5 %

Let The earning of plant after t years = A( t )

So,

The earning of plant after t years = initial earning × (1+ \dfrac{\textrm rate}{100})^{\textrm Time}

Or, A(t) = $ 80 × (1+ \dfrac{\textrm 5}{100})^{\textrm t}

or, A(t) = $ 80 × (1.05)^{\textrm t}

Hence The amount that plant earns per man hour after (t) years it open is   $80 (1.05)^{\textrm t} . Answer

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Kay [80]
1.75 yards .its simple you just have to see how much youll have to multiply by 4 to get 7
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21+[36devided(12-6)+2-5]multiply3
Alona [7]
12-6=6
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Coefficient of x^2 in expansion of (x+2)^5
iVinArrow [24]
The x² term will be C(5,2)x²·2³ = 80x².

The coefficient is 80.

_____
C(n, k) = n!/(k!·(n-k)!)
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