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alekssr [168]
3 years ago
11

The box plots below show the average gas mileage, in miles per gallon, of the cars sold at a dealership in June and in December.

Mathematics
2 answers:
natita [175]3 years ago
4 0

Answer:

The interquartile range for December should be 21 minus 18 = 3.

Step-by-step explanation:

Hope this helps!

STALIN [3.7K]3 years ago
3 0

Answer:

a force is any interaction that, when unopposed, will change the motion of an object. A force can cause an object with mass to change its velocity, i.e., to accelerate. Force can also be described intuitively as a push or a pull. A force has both magnitude and direction, making it a vector quantity.

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If you need $3,000 four years from now, how much would you need to deposit into an account that earns 5% interest, compounded an
Aleks04 [339]

Answer:

2468.11 dollars

Step-by-step explanation:

Amount that should be available after four years =3000 $

Interest rate = 5%

No of years =4

Let P be the principal invested

Then 3000=P(1+0.05)^4\\P=3000(1.05)^{-4} \\=2468.11

Hence 2468.11 dollars should be deposited to get 3000 dollars after 4 years at 5% interest.

6 0
3 years ago
Let the region R be the area enclosed by the function f(x)=ln(x) and g(x)= 1/2x-2. Find the volume of the solid generated when t
Neporo4naja [7]

Answer:

V=61.66

Step-by-step explanation:

This problem can be solved by using the expression for the Volume of a solid with the washer method

V=\pi \int \limit_a^b[R(x)^2-r(x)^2]dx

where R and r are the functions f and g respectively (f for the upper bound of the region and r for the lower bound).

Before we have to compute the limits of the integral. We can do that by taking f=g, that is

f(x)=g(x)\\ln(x)=\frac{1}{2}x-2

there are two point of intersection (that have been calculated with a software program as Wolfram alpha, because there is no way to solve analiticaly)

x1=0.14

x2=8.21

and because the revolution is around y=-5 we have

R=ln(x)-(-5)\\r=\frac{1}{2}x-2-(-5)\\

and by replacing in the integral we have

V=\pi \int \limit_{x1}^{x2}[(lnx+5)^2-(\frac{1}{2}x+3)^2]dx\\

V=\pi [28x+\frac{1}{x}+xln^2x-12xlnx-6lnx]  

and by evaluating in the limits we have

V=61.66

Hope this helps

regards

3 0
3 years ago
Are these two functions inverse of each other? 3 g(x) + = 4x + 3 and f(x) = -x f(x) = -~- 4 Ο Νο O Yes​
Art [367]

Answer:

Yes!

Step-by-step explanation:

3 0
4 years ago
Please help me :) with this math problem, it's exponential functions.
noname [10]

Answer:

f(x) = 9(5/3)^x

Step-by-step explanation:

f(x) = a(b^x)

x = 0

9 = a(b⁰)

9 = a

f(x) = 9(b^x)

x = 1

15 = 9(b¹l

b = 15/9

b = 5/3

f(x) = 9(5/3)^x

8 0
4 years ago
Which statement is true regarding the graphed functions?
Zigmanuir [339]

Answer:

the answer to your question is f(2)=0 and g(-2)=0

4 0
3 years ago
Read 2 more answers
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