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jeka94
3 years ago
9

Ava draws a circle with radius 4 cm. Elliana draws a circle with diameter 6 cm. Without calculating, whose circle has the greate

r area? Explain.
Mathematics
1 answer:
Valentin [98]3 years ago
6 0

Answer:

\huge\boxed{\texttt{Ava\textsc{\char13}s circle}}

Step-by-step explanation:

We can use the relationship between a radius and a diameter to find which circle has a greater area without calculating it.

We know that the diameter is twice the size of the radius.

  • The diameter is the distance across the circle at the center
  • The radius is the distance from the center of a circle to the edge

Using this, we can find the radius of a circle that has a diameter of 6.

Since the diameter is twice the radius, the radius will be half the diameter.

Since the diameter is 6, the radius is 3.

Circle areas can be calculated with the following formula, where r is the radius:

\pi r^2

Using this, we know that a higher value of r will get us a greater area. Therefore, we know that the greater value (3 or 4) will get us the greater area.

Since 4 is greater than 3, we know that the circle with the radius of 4 (Ava’s) will have a greater area.

Hope this helped!

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2 years ago
prove that the quadrilateral whose vertices are the points A(-1,1), B(-3,4), C(1,5) and D(3,2) is a parallelogram.
Vsevolod [243]

Answer:

Since \overrightarrow{AB} = \overrightarrow{DC} and \overrightarrow{AD} = \overrightarrow{BC}, then the quadrilateral ABCD is a parallelogram.

Step-by-step explanation:

First, we label each point of the quadrilateral with the help of a graphing tool. If the quadrilateral ABCD is a parallelogram, then \overrightarrow{AB} = \overrightarrow{DC} and \overrightarrow{AD} = \overrightarrow{BC}. If we know that A(x,y) =(-1, 1), B(x,y) =(-3,4), C(x,y) = (1,5) and D(x,y) = (3,2), then the measure of each vector is, respectively:

\overrightarrow{AB} = (-3,4)-(-1,1)

\overrightarrow{AB} = (-2, 3)

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\overrightarrow{DC} = ( -2,3)

\overrightarrow{AD} = (3,2)-(-1,1)

\overrightarrow{AD} = (4, 1)

\overrightarrow{BC} = (1,5)-(-3,4)

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Since \overrightarrow{AB} = \overrightarrow{DC} and \overrightarrow{AD} = \overrightarrow{BC}, then the quadrilateral ABCD is a parallelogram.

7 0
3 years ago
Which of the following can be used to prove that triangle EFG is also a right triangle?
galben [10]

Answer:

Prove that KL is equal to c by Pythagorean Theorem.


Step-by-step explanation:

In the two triangles triangle KLM is a right triangle with sides a and b as the two legs of the right triangle .We can apply Pythagorean Theorem to find KL.

In triangle KGF two sides are a and b .If we prove KL=EF then Pythagorean Theorem will be true for triangle KGF and hence we can prove triangle KGF to be a right triangle.

The correct option to prove triangle KGF to be a right triangle is to Prove that KL is equal to c by Pythagorean Theorem.


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3 years ago
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Answer:

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Step-by-step explanation:

you'd start by multiplying 6 by everything in the first pair of parentheses:

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then you'd add the like terms together:

(-12.6k-12)+(7k+5)= -5.6k-7

8 0
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