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2 years ago

What is the area of the circle shown above ? round to the nearest 10th please help with homework

Mathematics

1 answer:

kherson [118]2 years ago

8 0

To calculate the area of the circle, make sure to use the equation. A = Pi r^2, since the diameter is given divide by 2 to get the radius and plug into the equation.

Then locate the decimal place that is hundredths and round

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Use the simple interest formula to find the interest earned for $347 at 9.63% for 5 years

san4es73 [151]

Answer:

$167.08

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 9.63%/100 = 0.0963 per year,

then, solving our equation

I = 347 × 0.0963 × 5 = 167.0805

I = $ 167.08

The simple interest accumulated

on a principal of $ 347.00

at a rate of 9.63% per year

for 5 years is $ 167.08.

8 0

2 years ago

PLEASE HELP !!?!??!?!?!?!!

tatiyna

Answer:

yes yes no

Step-by-step explanation:

6 0

2 years ago

The minute hand on an analog clock is 8 inches long. how far does the tip of the minute hand travel in 16 minutes

Dahasolnce [82]

We know that
<span>on an analog clock
60 minutes is equal to a circumference of 360</span>°
so
360/60-----> 6°
that means
1 minute is equal to --------> 6°
16 minutes----------> X
x=16*6-----> 96°

the length of a circumference=2*pi*r
for r=8 in

the length of a circumference=2*pi*8-----> 50.24 in

if 360° (full circle) has a length of----------------> 50.24 in
96°---------------------------> x
x=96*50.24/360------> x=13.40 in

the answer is
13.40 in

5 0

2 years ago

I need help...........

harina [27]

Answer:

Step-by-step explanation:

8 0

2 years ago

Two particles travel along the space curves r1(t) = t, t2, t3 r2(t) = 1 + 2t, 1 + 6t, 1 + 14t . Find the points at which their p

GuDViN [60]

Answer:

A) points at which paths intersect : (1,1,1) ; (2,4,8)

B) DNE

Step-by-step explanation:

A) To find the points in which the particle paths intersect, it is necessary to find the values of t for which the three components of both vectors are equal:

$t_1=1+2t_2\\\\t_1^2=1+6t_2\\\\t_1^3=1+14t_2$

you replace t1 from the first equation in the second equation:

$(1+2t_2)^2=1+6t_2\\\\1+4t_2+4t_2^2=1+6t_2\\\\4t_2^2-2t_2=0\\\\t_2(2t_2-1)=0\\\\t_2=0\\\\t_2=\frac{1}{2}$

Then, for t2 = 0 and t2=1/2 you obtain for t1:

$t_1=1+2(0)=1\\\\t_1=1+2(\frac{1}{2})=2$

Hence, for t1=1 and t2=0 the paths intersect. Furthermore, for t1=2 and t2=1/2 the paths also intersect.

The points at which the paths intersect are:

$r_1(1)=(1,1,1)=r_2(0)=(1,1,1)\\\\r_1(2)=(2,4,8)=r_2(\frac{1}{2})=(2,4,8)$

B) You have the following two trajectories of two independent particles:

$r_1(t)=(t,t^2,t^3)\\\\r_2(t)=(1+2t,1+6t,1+14t)$

To find the time in which the particles collide, it is necessary that both particles are in the same position on the same time. That is, each component of the vectors must coincide:

$t=1+2t\\\\t^2=1+6t\\\\t^3=1+14t$

From the first equation you have:

$t=1+2t\\\\t=-1$

This values does not have a physical meaning, then, the particle do not collide

answer: DNE

5 0

3 years ago