3 years ago

Find the value of x Please help

Mathematics

1 answer:

IrinaK [193]3 years ago

5 0

Answer:

128 degrees

Step-by-step explanation:

360-90-90-52=128

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8_murik_8 [283]

Then it’s 20 units I think

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3 years ago

What does it mean to be a 'solution' to a function?

serg [7]

A number is a solution when it fits within the range of answers that the function generates.

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PLEASE ANSWER ASAP! MUST BE WITH WITH WITH WITH WWWWWIIIIIIIITTTTTHHHH AN EXPLANATION IN ORDER TO RECEIVE POINTS & BRAINLIES

Dahasolnce [82]

Easy peasy pumpin easy

split it up (make in to net and unfold or something)

2 triangles (identical)
2 side rectangles (identical
1 base

area of rectangle=lh or wl etc
area of triangle=1/2bh

triangles
b=16
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answer is C

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3 years ago

Determine the value of x in the diagram? A.32 B.10 C.20 D.16

Gnesinka [82]

Answer:

B. 10

Step-by-step explanation:

These are vertical angles meaning they are also equal.

$4x-12=2x+8\\2x-12=8\\2x=20\\x=10$

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3 years ago

Read 2 more answers

Let f ( x , y )=5 x and let C be the segment of the parabola y = 2 x squared joining O( 0 , 0 ) and P( 1 , 2 ). a. Find a parame

taurus [48]

a. We can parameterize $C$ by

$x=t$

$y=2t^2$

with $0\le t\le1$ . Then

$\displaystyle\int_C5x\,\mathrm dS=\int_0^15t\sqrt{1+16t^2}\,\mathrm dt=\dfrac5{48}(17^{3/2}-1)$

b. We can parameterize the opposite direction by instead setting

$x=1-t$

$y=2(1-t)^2$

with $0\le t\le 1$ . Then

$\displaystyle\int_C5x\,\mathrm dS=\int_0^15(1-t)\sqrt{1+16(1-t)^2}\,\mathrm dt=-\int_1^05u\sqrt{1+16u^2}\,\mathrm dt=\int_0^15u\sqrt{1+16u^2}\,\mathrm du$

which gives the same value as in part (a).

5 0

3 years ago