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maksim [4K]
2 years ago
7

Plz only do what i have not done

Mathematics
1 answer:
Gennadij [26K]2 years ago
8 0

Answer:

7- B,A,C

8- J,A,L

9- D,E,F

10- C,D,E

11- B,A,C

12- X,Z,Y

I hope this helps!

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creativ13 [48]

The mean exists at 3 and the standard deviation exists 0.87.

Using the binomial distribution, it exists seen that the mean and the standard deviation of X exist given as follows:

$\mu_{X}=3, \sigma_{X}=0.87

<h3>What is the binomial probability distribution?</h3>

The expected value of the binomial distribution exists:

$\mu_{X}=n p$$

The standard deviation of the binomial distribution exists:

$\sigma_{X}=\sqrt{n p(1-p)}$$

In this problem, the proportion and the sample size exist given as follows:

p = 0.75

n = 4

Therefore, the mean and the standard deviation exist given by:

$&\mu_{X}=n p=4(0.75)=3 \\

$&\sigma_{X}=\sqrt{n p(1-p)}

$=\sqrt{4(0.75)(0.25)}=0.87

The mean exists at 3 and the standard deviation exists 0.87.

To learn about the binomial distribution refer to:

brainly.com/question/24863377

#SPJ4

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1 year ago
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Answer:

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