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Elena-2011 [213]

3 years ago

12

A chili cook-off has adult tickets (a) and child tickets (c) . A group of Visitors buy three adult tickets and two child tickets

and pays a total of $26. Another group buys five adult tickets and 3 child tickets and pays $42. Write and solve a system of equations to find the price of each type of ticket. (I just need the equations)

1 answer:

77julia77 [94]3 years ago

4 0

Answer:

Equation 1 would be: 3a+2C

Equation 2 would be: 5a+3C

Step-by-step explanation:

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jenny has 68 1/2 pages of her left to read. How many pages will she have left after she reads 26 1/6 pages?

jekas [21]

Answer:

42 1/3

Step-by-step explanation:

We subtract 26 1/6 from 68 1/2. We do this by finding the LCM of 6 and 2. That is 6. We multiply 1/2 by 3/3 to get 3/6. Now, we subtract. 68 - 26 is 42, and 3/6 - 1/6 is 2/6. Our answer is 42 2/6. That can be simplified to 42 1/3.

6 0

3 years ago

BRAINLIEST !!! please dont answer if you do not know it

postnew [5]

Answer:

The answer is A.

Step-by-step explanation:

There are Four 6's, Four 4's, Seven 5's, One 2, Two 3's, Two 7's, and One 8.

Hope this helps :))

7 0

3 years ago

Solve step by step solution then only i can do it plxx

Anuta_ua [19.1K]

Answer:

<h3><u>Let's</u><u> </u><u>understand the concept</u><u>:</u><u>-</u></h3>

Here angle B is 90°

So $\triangle ABC$ and $\triangle ABD$ Are right angled triangle

So we use Pythagoras thereon for solution

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>

First in triangle ABC

perpendicular=p=8cm

Hypontenuse =h =10cm

We need to find base=b

According to Pythagoras thereon

${\boxed{\sf b^2=h^2-p^2}}$

Substitutethe values

$\longrightarrow$ $\sf b^2=10^2-p^2$

$\longrightarrow$ $\sf b={\sqrt {10^2-8^2}}$

$\longrightarrow$ $\sf b={\sqrt{100-64}}$

$\longrightarrow$ $\bf b={\sqrt {36}}$

$\longrightarrow$ $\sf b=6$

$\therefore$ $\overline{BC}=6cm$

BD=BC+CD

$\longrightarrow$ $BD=9+6$

$\longrightarrow$ $BD=15cm$

Now in $\triangle ABD$

Perpendicular=p=8cm

Base =b=15cm

We need to find Hypontenuse =AD(x)

According to Pythagoras thereon

${\boxed {\sf h^2=p^2+b^2}}$

Substitute the values

$\longrightarrow$ $\sf h^2=8^2+15^2$

$\longrightarrow$ $\sf h={\sqrt {8^2+15^2}}$

$\longrightarrow$ $\sf h={\sqrt {64+225}}$

$\longrightarrow$ $\sf h={\sqrt {289}}$

$\longrightarrow$ $\sf h=17cm$

$\therefore$ ${\underline{\boxed{\bf x=17cm}}}$

3 0

3 years ago

Martha drew a pair of intersecting non-perpendicular lines, I and m. She numbered one pair of vertical angles <1 and <2, a

RUDIKE [14]

Answer:

D. Because <1 and <2 are each supplementary to <3, they are therefore congruent

Step-by-step explanation:

A. m<1 + m<2 + m<3 + m<4 = 360

Incorrect in terms of the proof

B. The sum of the measures of angles of a triangle is 180°

Not relevant

C. The measure of all right is 90°

Not relevant

D. Because <1 and <2 are each supplementary to <3, they are therefore congruent

Correct

8 0

3 years ago

PLEASE HELP!!!! Complete the proof for the following conjecture. WILL GIVE BRAINLIEST!

Darina [25.2K]

Huh I 8 so yeah bye nice talking to ya

5 0

3 years ago