A(n)=4+4(n-1)
a(n)=4+4n-4
a(n)=4n
76=4n
n=19
The sum of any arithmetic sequence (series are infinite) is:
(a+a(n))(n/2)
The average of the first and last terms times the number of terms, in this case we found that n=19 so:
19(4+76)/2=760
36 < 39 < 49
√36 < √39 < √49
6 < √39 < 7
√39 ≈ 6
Answer:
16+A
Step-by-step explanation:
4*4=16
X
--- × 56 =18
100
56x = 18×100
× = 18 × 100
- - - - - - -
56
X = 32.14%
