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Harrizon [31]
2 years ago
5

Please help im desperate for my grade to go up

Mathematics
1 answer:
Semenov [28]2 years ago
7 0

Answer:

A.) 6iV5

B.) i=V-1 or -1

C.) 11-2i

D.) 10+10i

Step-by-step explanation:

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olga2289 [7]
A^3
a to the power of three
6 0
2 years ago
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In the diagram, lines AB , CD, and EF intersect at G
Ghella [55]

Answer:

D. 70°

Step-by-step explanation:

Given:

m<DGB = 35°

m<CGF = 75°

Required:

m<AGE

SOLUTION:

m<EGD = m<CGF (vertical angles are congruent)

m<EGD = 75°

m<AGE + m<EGD + m<DGB = 180° (angles on a straight line)

m<AGE + 75° + 35° = 180° (substitution)

m<AGE + 110° = 180°

Subtract 110 from each side of the equation

m<AGE = 180° - 110°

m<AGE = 70°

6 0
2 years ago
Verify sin^4 x - sin^2 x = cos^4 x - cos^2 x is an identity
Citrus2011 [14]

Answer:

(identity has been verified)

Step-by-step explanation:

Verify the following identity:

sin(x)^4 - sin(x)^2 = cos(x)^4 - cos(x)^2

sin(x)^2 = 1 - cos(x)^2:

sin(x)^4 - 1 - cos(x)^2 = ^?cos(x)^4 - cos(x)^2

-(1 - cos(x)^2) = cos(x)^2 - 1:

cos(x)^2 - 1 + sin(x)^4 = ^?cos(x)^4 - cos(x)^2

sin(x)^4 = (sin(x)^2)^2 = (1 - cos(x)^2)^2:

-1 + cos(x)^2 + (1 - cos(x)^2)^2 = ^?cos(x)^4 - cos(x)^2

(1 - cos(x)^2)^2 = 1 - 2 cos(x)^2 + cos(x)^4:

-1 + cos(x)^2 + 1 - 2 cos(x)^2 + cos(x)^4 = ^?cos(x)^4 - cos(x)^2

-1 + cos(x)^2 + 1 - 2 cos(x)^2 + cos(x)^4 = cos(x)^4 - cos(x)^2:

cos(x)^4 - cos(x)^2 = ^?cos(x)^4 - cos(x)^2

The left hand side and right hand side are identical:

Answer:  (identity has been verified)

3 0
3 years ago
Use only an associative property to rewrite the following expression.<br> (pk)•r=
Gennadij [26K]

Answer:

Step-by-step explanation:

(pk) * r = p * (kr)

5 0
3 years ago
Martha constructs the table below to show the relationship between her cell phone's age and the amount of time it takes to charg
Alexeev081 [22]

Answer:

D

Step-by-step explanation:

To find the rate of increase all you have to do is take one of the data sets to see that every two months its charge time increases by 15 minutes or 7.5 minutes every month.

4 0
2 years ago
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