When you have something like this, all you need to do is substitute the values, the last is for what value of x
For the first one;
((x^2+1)+(x-2))(2)
(x^2+x-1)(2)
(2)^2+(2)-1
4+2-1
5
For the second one;
((x^2+1)-(x-2))(3)
(x^2-x+3)(3)
(3)^2-(3)+3
9-3+3
9
For the last one;
3(x^2+1)(7)+2(x-2)(3)
3((7)^2+7)+2((3)-2)
3(49+7)+2(3-2)
3(56)+2(1)
168+2
170
Answer:
125($54000) = $6750 is the decrease
$54,000 - $6,750 = $47,250 is the price of the next model
Step-by-step explanation:
Answer:
the range is {7,5,1}
Step-by-step explanation:
To find the range, just plug in the domain into the function.
f(-1) = -2(-1) + 5 = 7
f (0) = -2(0) + 5 = 5
f(2) = -2(2) + 5 = 1
I could be wrong but I think A or B
Answer:
4 I think
Step-by-step explanation:
If im thinking this out correctly you would divide 32 by the number of q which would be 32 divided by 8 which is 4.
I HOPE THIS HELPS!!