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ohaa [14]
3 years ago
10

What is the solution to the following equation?

Mathematics
2 answers:
Mekhanik [1.2K]3 years ago
6 0
Equation:  5(2x - 6) + 20 = 10


Simplify both sides of equation:
5(2x - 6) + 20 = 10

(5)(2x) + (5)(- 6) + 20 = 10   (Distribute)

10x +   - 30 + 20 = 10

(10x) + (- 30 + 20) = 10   (Combine Like terms)

10x +   - 10 = 10

10x - 10 = 10


Add 10 to both sides:
10x - 10 + 10 = 10 + 10

10x = 20



Divide both sides by 10:

10x/10 = 20/10
x  =  2



Answer: x = 2





Hope that helps!!!! ( answer: Letter Choice (D), x = 2



Troyanec [42]3 years ago
4 0
First, distribute 5 into the parentheses:
10x - 30 + 20 = 10
Combine like terms:
10x - 10 = 10
Isolate x by adding 10 to both sides:
10x = 20
Divide both side by 10:
x = 2
D is the right answer.
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Since the line stops at the point (6, 7), then it means that the height of the triangle made is 7 units and the base is 6 units long.
An angle, θ, is made at the line that joins the origin and the point (6, 7).

tan \theta = \frac{opp}{adj}
tan \theta = \frac{height}{base} = \frac{7}{6}

Hence, tan \theta = \frac{7}{6}
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A circle is centered O (0,0) and has the radius 3.46410161514 where does poing M (-3,2) lie​
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The circle area can be defined as x2 + y2 < 3.46^2.

For point M, x2 + y2 = 13.

Since 3.46^2 is about 12, point M is outside the circle!

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Which are the solutions of the quadratic equation x^2=-5x-3
frutty [35]
The correct answer would be \frac{-5 +/-  \sqrt{13} }{2}

In order to solve for this you must first get the equation equal to 0. 

<span>x^2=-5x-3 ----> add 5x to both sides. 
x^2 + 5x = -3 ----> add 3 to both sides.
x^2 + 5x + 3 = 0

Now knowing this we can use the coefficients of each one in descending order of power as a, b and c. 

a = 1 (because it is the coefficient to x^2)
b = 5</span> (because it is the coefficient to x)
c = 3 (because it is the end number)

Now we can plug these values into the quadratic equation. 

\frac{-b +/-  \sqrt{b^{2} - 4ac } }{2a}

\frac{-5 +/- \sqrt{5^{2} - 4(3)(1) } }{2(1)}

\frac{-5 +/- \sqrt{13} }{2}

And those would be your two answers.
5 0
3 years ago
Which equation represents a line that passes through (4,1/3) and has a slope of 3/4?
velikii [3]
We can use the point-slope equation:
y = mx + b
m, the slope, is 3/4:
y =  \frac{3}{4} x + b
To find b, we plug in the point (4,1/3):
( \frac{1}{3} ) =  \frac{3}{4} (4) + b \\  \frac{1}{3}  = 3 + b \\  \frac{1}{3} =  \frac{9}{3}  + b
-  \frac{8}{3}  = b

Therefore, the point-slope equation is
y =  \frac{3}{4} x -  \frac{8}{3}

Now we have to see which answer matches.


y -  \frac{3}{4}  =  \frac{1}{3} (x - 4) \\ y -  \frac{3}{4}  =  \frac{1}{3} x -  \frac{4}{3}  \\ y -  \frac{9}{12}  =  \frac{1}{3} x -  \frac{16}{12}
y =  \frac{1}{3} x -  \frac{7}{12}
Since this is not the same, we try the next one.


y -  \frac{1}{3}  =  \frac{3}{4} (x - 4) \\ y -  \frac{1}{3}  =  \frac{3}{4} x - 3 \\ y -  \frac{1}{3}  =  \frac{3}{4} x -  \frac{9}{3}
y =  \frac{3}{4} x -  \frac{8}{3}

This is the same, so this is the answer. We should still double-check the other answers.

y -  \frac{1}{3}  = 4(x -  \frac{3}{4} ) \\ y -  \frac{1}{3}  = 4x - 3 \\ y -  \frac{1}{3}  = 4x -  \frac{9}{3}
y = 4x -  \frac{8}{3}
This one is not equivalent.

y - 4 =  \frac{3}{4} (x -  \frac{1}{3} ) \\ y - 4 =  \frac{3}{4} x -  \frac{1}{4}  \\ y -  \frac{16}{4}  =  \frac{3}{4} x -  \frac{1}{4}
y =  \frac{3}{4} x +  \frac{15}{4}
This one also does not work.


The answer is the second one:
y -  \frac{1}{3}  =  \frac{3}{4} (x - 4)
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