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Answer:
x = 2 + sqrt(5) or x = 2 - sqrt(5)
Step-by-step explanation using the quadratic formula:
Solve for x over the real numbers:
7 (x^2 - 4 x - 1) = 0
Divide both sides by 7:
x^2 - 4 x - 1 = 0
Add 1 to both sides:
x^2 - 4 x = 1
Add 4 to both sides:
x^2 - 4 x + 4 = 5
Write the left hand side as a square:
(x - 2)^2 = 5
Take the square root of both sides:
x - 2 = sqrt(5) or x - 2 = -sqrt(5)
Add 2 to both sides:
x = 2 + sqrt(5) or x - 2 = -sqrt(5)
Add 2 to both sides:
Answer: x = 2 + sqrt(5) or x = 2 - sqrt(5)
<span>(3x^2+3)(4+x^3)
=</span><span>12x^2 +3x^5 + 12 + 3x^3
= </span>3x^5 + 3x^3 + 12x^2 + 12
Answer:
x ≤ 8
Step-by-step explanation:
Given
2x - 4 ≤ 12
Isolate the term in x by adding 4 to both sides
2x ≤ 16 ( divide both sides by 2 )
x ≤ 8 ← is the solution
The Answer For Number Two Is Negative 14