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goldfiish [28.3K]

2 years ago

13

A paint manufacturer discovers that the mean volume of paint in a gallon-sized pail is 1 gallon with a standard deviation of 0.0

5 gallons. The paint volumes are approximately bell-shaped. Estimate the percent of pails with volumes between 0.95 gallons and 1.05 gallons.

1 answer:

Agata [3.3K]2 years ago

5 0

Answer:

Approximately 68%.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 1, standard deviation = 0.05.

Estimate the percent of pails with volumes between 0.95 gallons and 1.05 gallons.

0.95 = 1 - 0.05

1.05 = 1 + 0.05

So within 1 standard deviation of the mean, which by the Empirical Rule, is approximately 68% of values.

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A group of students wants to determine the favorite snack food at their school. They know they should use a sample because the s

e-lub [12.9K]

To create a survey and hand them out to different students

7 0

2 years ago

Write an equation of the line shown. Then use the equation to find the value of x when y=112

PtichkaEL [24]

Answer:

$y = 8x + 16$

$x = 12$

Step-by-step explanation:

Given two points on the line (0, 16) and (3, 40), an equation for the line can be written using the slope-intercept line equation which takes the format $y = mx + b$ .

Where,

$m = slope = \frac{y_2 - y_1}{x_2 - x_1}$

b = y-intercept or the point at which the line cuts the y-axis.

Let's find slope (m) using the slope formula:

Let,

$(0, 16) = (x_1, y_1)$

$(3, 40) = (x_2, y_2)$

$slope (m) = \frac{40 - 16}{3 - 0}$

$slope (m) = \frac{24}{3}$

$slope (m) = 8$

Find b. Substitute the values of x = 0, y = 16, and m = 8 in the slope-intercept formula to find b.

$y = mx + b$

$16 = 8(0) + b$

$16 = 0 + b$

$16 = b$

$b = 16$

Plug in the values of m and b into the slope-intercept formula to get the equation of the line.

$y = mx + b$

$y = 8x + 16$

Let's use the equation to find x when y = 112.

$y = 8x + 16$

Substitute y = 112 in the equation

$112 = 8x + 16$

$112 - 16 = 8x$

$96 = 8x$

Divide both sides by 8

$12 = x$

$x = 12$

8 0

2 years ago

Shades R Us charges $20 per day to rent a lounge chair and $15 per day to rent an umbrella. Dan and Lisa paid a total of $245 to

goblinko [34]

Answer:

$151.88 costs to Dan algebraic form

$245/2 = $122.50+20+15 = 157.5 is the answer though.

Step-by-step explanation:

35x+20(x-1)

35x + (20x -1)

35x +20x -1

35x -20x-20

x= 53/11

53/11 = 4.81

4.81 x 20 = $96.20 on chairs

4.81 x 15 = 72.15 on umbrella

96+72 = 168.35

245-168.35 = 76.65

76.65 + 20 = 96.65

Because we subtracted to get 168.35 we have the difference of $15 which is the difference of what he and she paid we half this amount = $7.50 half the 0.45 additional found on Dans $96.65 = $0.22 and find $7.72 balance to add to his 96.20

Added together his costs out of 245 was $104.37+ 76.65 = $181.20

Costs of umbrella = 76.65/2 = 39.325

181.20 -29.325=151.87 rounded up to 151.87

As x = 53/11 the decimal of this is 4.81 = x

6 0

2 years ago

Alan bought 20 yards of fencing. He used 5.9 yards in one garden and 10.3 in another. Write remaining as a fraction in simplest

Over [174]

Its 3.8 because if you add 5.9 and 10.3 is 16.2, and if you subtract it by 20, it should equal 3.8.

7 0

2 years ago

Read 2 more answers

Liquid A has a density of 0.7g/cm^3

TiliK225 [7]

$\rho = \frac{m}{V} \Rightarrow V=\frac{m}{\rho}$
ρ - density, m - mass, V - volume

Liquid A:
$\rho=0.7 \ \frac{g}{cm^3} \\
m=140 \ g \\
\\ V=\frac{140 \ g}{0.7 \ \frac{g}{cm^3}}=200 \ cm^3$

Liquid B:
$\rho=1.6 \ \frac{g}{cm^3} \\
m=128 \ g \\
\\ V=\frac{128 \ g}{1.6 \ \frac{g}{cm^3}}=80 \ cm^3$

Liquid C:
$m=140 \ g + 128 \ g=268 \ g \\
V=200 \ cm^3 + 80 \ cm^3=280 \ cm^3 \\ \\
\rho=\frac{268 \ g}{280 \ cm^3} \approx 0.96 \ \frac{g}{cm^3}$

The density of liquid C is approximately 0.96 g/cm³.

5 0

3 years ago

Read 2 more answers