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Anna [14]
3 years ago
11

What is the length of AD if A is located at (-7,0) and D is located at (8,0)?

Mathematics
1 answer:
Kryger [21]3 years ago
6 0

Answer:

15

Step-by-step explanation:

(-7,0) and (8,0) are on the opposite side of origin of x axis

d = 8 - -7 = 15

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This table shows a value that represents an exponential function what is the average rate of change for this function for the in
aliya0001 [1]

Answer:

Option A is correct, i.e. 12.

Step-by-step explanation:

Given is the table of x&y relationship which represents an exponential function.

The average rate of change for a function can be found using the following formula:-

F_average = { f(b) - f(a) } / (b-a)

Given a = 3 and b = 5.

From the table, f(3) = 8 and f(5) = 32.

So, F_average = (32-8)/(5-3)

F_average = 24/2 = 12.

Hence, option A is correct, i.e. 12.

4 0
3 years ago
Can someone help me with this math homework please!
Misha Larkins [42]

Answer:

Step-by-step explanation:

In step one she has added 1x to each side of the statement

in step two she has taken five away from both sides of the equation therefore simplifying the entire equation

in step three she divided both sides by three to have the unknown value on one side of the equation

6 0
3 years ago
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joja [24]

Answer:

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Step-by-step explanation:

7 0
3 years ago
If f(a)=4a-5 what is f(3)-f(1.25)
ladessa [460]

Answer:

f(a)=4a-5

1:    a=  -5  / f−4

f(3)-f(1.25)

2:   1.75f

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A person borrowef Rs 16000 from a bank at 12.5% pet annum simple intrest and lent the whole amount to shopkeeper at the sam rate
r-ruslan [8.4K]

Answer:

The amount he gains in 2 years is Rs. 250

Step-by-step explanation:

The parameters of the amount borrowed from the bank are;

The amount borrowed, P = Rs. 16,000

The interest rate of the amount borrowed, R = 12.5%

The number of years, T = 2 years

The simple interest, I = (P × R × T)/100 =  (Rs. 16,000 × 12.5 × 2)/100 = Rs. 4,000

The total amount the person is to pay bank to the bank = P + I = Rs. 16,000 + Rs. 4,000 = Rs. 20,000

The parameters of the amount lent to the shopkeeper are;

The amount lent, P = Rs. 16,000

The compound interest rate of the amount lent, R = 12.5%

The number of years, T = 2 years

The amount he receives from the shopkeeper after 2 years, A = P·(1 + R/n)^(n × T) = Rs. 16,000 × (1 + 0.125/1)^(1 × 2) = Rs. 20,250

The amount he gains in 2 years = The amount he receives from the shop keeper - The amount he gives to the bank = Rs. 20,250 - Rs. 20,000 = Rs. 250

The amount he gains in 2 years = Rs. 250.

8 0
3 years ago
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