1. You should draw a diagram with the information given in the problem. As you can see in the figure attached, there are two triangles, so, you can calculate the height of the lamp post as below:
h1/b1=h2/b2
h1 is the height asked.
b1=360 cm+ 90 cm
b1=450 cm
h2=160 cm
b2=90 cm
2. When you substitute these values into h1/b1=h2/b2, you obtain:
h1/450 cm=160 cm/90 cm
3. Now, you must clear the height "h1". Then, you have:
h1=(160 cm)(450 cm)/90 cm
h1=72000 cm²/90 cm
h1=800 cm
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How high is the lamp post?
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The answer is: 800 cm
Steps:
1. calculate the values of y at x=0,1,2. using y=5-x^2
2. calculate the areas of trapezoids (Bottom+Top)/2*height
3. add the areas.
1.
x=0, y=5-0^2=5
x=1, y=5-1^2=4
x=2, y=5-2^2=1
2.
Area of trapezoid 1 = (5+4)/2*1=4.5
Area of trapezoid 2 = (4+1)/2*1=2.5
Total area of both trapezoids = (4.5+2.5) = 7
Exact area by integration:
integral of (5-x^2)dx from 0 to 2
=[5x-x^3/3] from 0 to 2
=[5(2-0)-(2^3-0^3)/3]
=10-8/3
=22/3
=7 1/3, slight greater than the estimation by trapezoids.