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Allushta [10]
3 years ago
11

A girl stands 160 cm tall she stands 360 cm away from a lamp post at night her shadow from the light is 90 cm long how high is t

he lam post

Mathematics
1 answer:
frozen [14]3 years ago
6 0
1. You should draw a diagram with the information given in the problem. As you can see in the figure attached, there are two triangles, so, you can calculate the height of the lamp post as below:
 
 h1/b1=h2/b2
 
 h1 is the height asked.
 b1=360 cm+ 90 cm
 b1=450 cm
 h2=160 cm
 b2=90 cm
 
 2. When you substitute these values into  h1/b1=h2/b2, you obtain:
 
 h1/450 cm=160 cm/90 cm
 
 3. Now, you must clear the height "h1". Then, you have:
 
 h1=(160 cm)(450 cm)/90 cm
 h1=72000 cm²/90 cm
 h1=800 cm
<span> 
 How high is the lamp post?
</span> 
 The answer is: 800 cm

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6 0
3 years ago
Jill has a photograph that is 4 inches wide by 6 inches high. If she enlarges it so that the width is 12
Nadya [2.5K]

Answer:

The inches in height will be 18 inches.

Step-by-step explanation:

Okay so we know that the original width is 4 inches and she enlarged that to 12 inches

So what we first have to do is find out how much did the photograph "grow" per se. To find this we have to divide 12 by 4. 12 divided by 4 = 3.

So, the width of the photograph grew "times 3" inches

Now whatever you do to the width you have to do to the height. In this case, what is "3 times" 6 (which is the height). 3 times 6 = 18 inches

So in simpler words 12 divided 4 = 3 x 6 = 18 inches

The inches in height will be 18 inches.

Jill has a square with a width of 12 inches, and a height of 18 inches.

Have a wonderful day!

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What is the unit rate of 72 ounces in 6 steaks
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4 0
3 years ago
(a) By inspection, find a particular solution of y'' + 2y = 14. yp(x) = (b) By inspection, find a particular solution of y'' + 2
SOVA2 [1]

Answer:

(a) The particular solution, y_p is 7

(b) y_p is -4x

(c) y_p is -4x + 7

(d) y_p is 8x + (7/2)

Step-by-step explanation:

To find a particular solution to a differential equation by inspection - is to assume a trial function that looks like the nonhomogeneous part of the differential equation.

(a) Given y'' + 2y = 14.

Because the nonhomogeneus part of the differential equation, 14 is a constant, our trial function will be a constant too.

Let A be our trial function:

We need our trial differential equation y''_p + 2y_p = 14

Now, we differentiate y_p = A twice, to obtain y'_p and y''_p that will be substituted into the differential equation.

y'_p = 0

y''_p = 0

Substitution into the trial differential equation, we have.

0 + 2A = 14

A = 6/2 = 7

Therefore, the particular solution, y_p = A is 7

(b) y'' + 2y = −8x

Let y_p = Ax + B

y'_p = A

y''_p = 0

0 + 2(Ax + B) = -8x

2Ax + 2B = -8x

By inspection,

2B = 0 => B = 0

2A = -8 => A = -8/2 = -4

The particular solution y_p = Ax + B

is -4x

(c) y'' + 2y = −8x + 14

Let y_p = Ax + B

y'_p = A

y''_p = 0

0 + 2(Ax + B) = -8x + 14

2Ax + 2B = -8x + 14

By inspection,

2B = 14 => B = 14/2 = 7

2A = -8 => A = -8/2 = -4

The particular solution y_p = Ax + B

is -4x + 7

(d) Find a particular solution of y'' + 2y = 16x + 7

Let y_p = Ax + B

y'_p = A

y''_p = 0

0 + 2(Ax + B) = 16x + 7

2Ax + 2B = 16x + 7

By inspection,

2B = 7 => B = 7/2

2A = 16 => A = 16/2 = 8

The particular solution y_p = Ax + B

is 8x + (7/2)

8 0
3 years ago
If $396 is invested at an interest rate of 13% per year and is compound continuously, how much will the investment be worth in 3
Sveta_85 [38]

Answer:

The investment at the end of the period will be $584.89.

Step-by-step explanation:

FV = PV e⁽ⁿˣ⁾

FV = Future Value = ?

PV = Present Value = $396

n = Interest Rate = 13%

x = time in years = 3

e = mathematical constant = 2.7183

FV = 396 x 2.7183⁽⁰°¹³ ˣ ³⁾

FV = 396 x 1.4770

FV = $584.89

7 0
3 years ago
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