v₀ = initial velocity of the freight train while it approach a road crossing = 16 km/h = 16 (5/18) m/s = 4.44 m/s
v = final velocity of the freight train after it crosses a road crossing = 65 km/h = 65 x 5/18 m/s = 18.06 m/s
t = time to do so = 10 min = 10 x 60 sec = 600 sec
acceleration is given as
a = (v - v₀ )/t
a = (18.06 - 4.44)/(600)
a = 0.023 m/s²
a = 294
Answer:
<h3>ᎪꪀsωꫀᏒ</h3>
x= 7
Step-by-step explanation:
2x=14
x= 14/2
x= 7
The 3rd answer, is correct.
Answer: 900
Step-by-step explanation:
Answer:
.43
Step-by-step explanation:
