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vesna_86 [32]
3 years ago
11

A roll of ribbon was 12 meters long. Diego cut 9 pieces of ribbon that were 0.4 meters each to tie some presents. He then used t

he remaining ribbon to make some wreaths. Each wreath required 0.6 meter.
How many meters of ribbon were available for making wreaths?

_____ meters

How many wreaths could Diego make with the available ribbon?

_______wreaths
Mathematics
2 answers:
Helen [10]3 years ago
7 0
Work and Reasoning:
We start off with 12m
Since there are 9 ribbons each 0.4 meters you have to do 9 • 0.4. Since that is 3.6m.
To find out how much ribbon you have left you must subtract the amount he used against the amount he had to begin with.
12 - 3.6 = 8.4
To find out how many wreaths he can make, you must divide the remaining amount of ribbon he has by the 0.6 meter.
8.4 divided by 0.6 is 14.

Answer:
He can make 14 wreaths with the remaining amount of ribbon.
dexar [7]3 years ago
4 0

Answer: 8.4; 14.

Step-by-step explanation:

To find how much ribbon we used to tie presents, we need to multiply 9 and 0.4.

9 x 0.4 = 3.6.

Diego used 3.6 meters of yard to tie some presents. We can subtract that from 12 to find how much ribbon we have left.

12 - 3.6 = 8.4.

We have 8.4 meters of ribbon to make wreaths.

Now we have to find how many wreaths we can make wiht 8.4 meters of ribbon. We know that each wreath needs 0.6, so we should divide 8.4 by 0.6 to find how many wreaths we can make.

8.4 ÷ 0.6 = 14.

Therefore, we can make 14 wreaths with the 8.4 meters of leftover ribbon.

(Part A's answer is 8.4, and Part B's answer is 14)

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Trapezoid QRST has two right angles. A 5-in.altitude can be drawn dividing QRDT into a rectangle and an isosceles right triangle
Vika [28.1K]

Answer:

The area of the trapezoid is 57.5 square inches

Step-by-step explanation:

we know that

The trapezoid QRST can be divided into a rectangle QRDT and an isosceles right triangle RSD

see the attached figure to better understand the problem

step 1

The area of rectangle is given by the formula

A=((QR)(RD)

we have

RD=5\ in ----> altitude

QR=9\ in

substitute

A=((9)(5)=45\ in^2

step 2

Find the area of the isosceles right triangle

The area of triangle is given by the formula

A=\frac{1}{2}(RD)(DS)

we have

RD=DS=5\ in ---> because is an isosceles triangle

substitute

A=\frac{1}{2}(5)(5)=12.5\ in^2

step 3

Adds the areas

A=45+12.5=57.5\ in^2

3 0
3 years ago
Read 2 more answers
The value of x for which 3 (x-2) = 2 (x+1)​
netineya [11]

Answer:

x = 8

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

Step-by-step explanation:

<u>Step 1: Define equation</u>

3(x - 2) = 2(x + 1)

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Distribute:                                     3x - 6 = 2x + 2
  2. Subtract 2x on both sides:          x - 6 = 2
  3. Add 6 to both sides:                    x = 8

<u>Step 3: Check</u>

<em>Plug in x into the original equation to verify it's a solution.</em>

  1. Substitute in <em>x</em>:                    3(8 - 2) = 2(8 + 1)
  2. Subtract/Add:                      3(6) = 2(9)
  3. Multiply:                               18 = 18

Here we see that 18 does indeed equal 18.

∴ x = 8 is a solution to the equation.

7 0
3 years ago
Find an equation of the circle and sketch it if it has: Center on y=4, tangent x-axis at (–2, 0)
Digiron [165]

Answer:

(x+2)^2+(y-4)^2=16

OK, lets start by drawing a basic graph (the first one) so we can visualize.

We already know that the y coordinate of the circle's center is 4.

We know that the circle is tangent to the X axis at (-2,0)

That means the x coordinate of the center has to be -2, as the tangent is a point on the edge of the circle that touches a line at exactly one point.

The radius is the distance from the center of the circle to its edge. We know the center's location now, it is (-2, 4) and a point on the edge of the circle (the tangent point) which is (-2,0). so the distance between the points is 4 which is the radius (you can use the distance formula, but it's quite oblivious.)

We can imagine the circle should look like this (the second one):

Now we can piece together an equation

The equation of a circle is (x-h)^2+(y-k)^2=r^2 where (h,k) is the center and r is the radius. When we put the numbers in: we get (x-(-2))^2+(y-(4))^2=4^2 which can be simplified into (x+2)^2+(y-4)^2=16 which is the answer.

Step-by-step explanation:

4 0
3 years ago
Por favor responder a esta pregunta
ahrayia [7]
Por determinante:
5...1...1
1...0...1 = 0 --> se o determinante for igual a 0, os pontos estarão alinhados.
3...3...1

calculando: (5 x 0 x 1 + 1 x 1 x 3 + 1 x 3 x 1) - (1 x 0 x 3 + 1 x 1 x 1 + 3 x 1 x 5) = 
0 + 3 + 3 - 0 - 1 - 15 = 
6 - 1 - 15 = 
5 - 15 = - 10 --> como não deu zero, os pontos não estão alinhados.
4 0
3 years ago
30.) Find the value of y: y/5+(-8)=-5<br>a. y = 5<br>b. Y= 10<br>c. Y = 15<br>d y = 20​
zheka24 [161]
The answer is c. Y=15
8 0
3 years ago
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