A diver is on the 10m platform, preparing to perform a dive. the diver's height above the water, in metres, at time t can be mod
elled using the equation : h(t)= -4.9(t)^2 + 2t + 10.. Estimate the rate at which the diver's height above the water is changing as the diver enters the water. be sure to include at least 3 intervals from booth sides in your table. I think its instantaneous rate of change..
We are given with 2 which means the initial velocity is 2 m/s and the height is 10 m initially. we are given the expression <span>h(t)= -4.9(t)^2 + 2t + 10. we can also use 2ay = Vf2 - Vo2 for three intervals: </span>2*9.8*7 = <span>Vf2 - 10^2; Vf is 15.40 m/s </span>2*9.8*8 = <span>Vf2 - 10^2; Vf is 16.02 m/s </span>2*9.8*9 = <span>Vf2 - 10^2; Vf is 16.63 m/s</span><span> </span>
