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AysviL [449]
2 years ago
15

After 8 points are added to each score in a sample.

Mathematics
1 answer:
mina [271]2 years ago
4 0
I think it’s 32 because it’s more simple then it looks! It would just be 40-8??
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Which expression is the result of factoring the expression below by taking out its greatest common factor?
Nat2105 [25]

Answer:

c is the correct answer

8 0
3 years ago
What Difference between hundreds and hundredths?
nordsb [41]

hundred means 100 or 200. Like I have 100 cats.

Hundredth means you have 1/100 of something. I have a peice of pie that is 1/100 of the pie. That means there are 100 pieces of the pie but I only have one out the hundred pieces.

hundred=100

hundredth = 1/100 = 0.01

tenth= 1/10 = 0.1

7 0
3 years ago
Read 2 more answers
Evaluate the integral. (sec2(t) i t(t2 1)8 j t7 ln(t) k) dt
polet [3.4K]

If you're just integrating a vector-valued function, you just integrate each component:

\displaystyle\int(\sec^2t\,\hat\imath+t(t^2-1)^8\,\hat\jmath+t^7\ln t\,\hat k)\,\mathrm dt

=\displaystyle\left(\int\sec^2t\,\mathrm dt\right)\hat\imath+\left(\int t(t^2-1)^8\,\mathrm dt\right)\hat\jmath+\left(\int t^7\ln t\,\mathrm dt\right)\hat k

The first integral is trivial since (\tan t)'=\sec^2t.

The second can be done by substituting u=t^2-1:

u=t^2-1\implies\mathrm du=2t\,\mathrm dt\implies\displaystyle\frac12\int u^8\,\mathrm du=\frac1{18}(t^2-1)^9+C

The third can be found by integrating by parts:

u=\ln t\implies\mathrm du=\dfrac{\mathrm dt}t

\mathrm dv=t^7\,\mathrm dt\implies v=\dfrac18t^8

\displaystyle\int t^7\ln t\,\mathrm dt=\frac18t^8\ln t-\frac18\int t^7\,\mathrm dt=\frac18t^8\ln t-\frac1{64}t^8+C

8 0
3 years ago
(Please correct answers only) (Will mark brainliest)
sergij07 [2.7K]
The answer is B., valid because people were chosen randomly
This would make it a valid survey
Hope this helps!
;3
8 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=f%28x%29%3D%203x%2B1%20%2C%20g%28x%29-%202x%20-1" id="TexFormula1" title="f(x)= 3x+1 , g(x)- 2
Bond [772]

Answer:

(fog)(x)=f(g(x))=2(3x+2)−1=6x+4−1=6x+3=3(2x+1)

8 0
3 years ago
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