Question

What is the distance between points (-2, -5) and (-14, 4) on the coordinate plane

Answer 1

Answer:

15 units

Step-by-step explanation:

$distance formula =\sqrt{(x_{2} -x_{1} )^{2} + (y_2 -y1)^{2} } }$

$x_{1} = -2\\x_{2} = -14\\y_{1} = -5\\y_{2} = 4$

$distance\\= \sqrt{(-14 - -2)^{2} + (4 - -5)^2 } \\= \sqrt{(-12)^2 + (9)^2} \\= \sqrt{144 + 81} \\= \sqrt{225} \\= 15\\Thus distance between the two points (-2,-5) and (-14,4) = 15 units$

Hope it helps....