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3 years ago

What is 4−2(3+2)2 ..................

Mathematics

1 answer:

rosijanka [135]3 years ago

5 0

Answer:

answer for this question is -16

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Help plz!! 100 points

Fynjy0 [20]

Answer:

t = 0, 1, 4, 8

h = 0, 12, 0 , 18

Step-by-step explanation:

t = 0 + 1 + 3 + 4

/ x1 - 5 (2) x + 4x + 9

h = 0, 12, 0, 18

After 18 seconds the ball attains...

x/3 = 1/4 - 4x 2(7) = 9/2 - 2 / 4 (0)

6 0

3 years ago

Read 2 more answers

(-4, 7), (-6,-4) find the slope of the line through each pair of points

HACTEHA [7]

Answer:

slope = 11/2

Step-by-step explanation:

If you are given two points, you can find the slope using the point-slope equation. The equation looks like this:

y₁ - y₂ = m(x₁ - x₂)

In this form, "m" represents the slope, "x₁" and "y₁" represent the values from one point, and "x₂" and "y₂" represent the values from the other point. You can plug the values from the points into the equation and simplify to find the slope.

Point 1: (-4, 7) Point 2: (-6, -4)

x₁ = -4 x₂ = -6

y₁ = 7 y₂ = -4

y₁ - y₂ = m(x₁ - x₂) <----- Point-slope form

7 - (-4) = m(-4 - (-6)) <----- Insert values

11 = m(2) <----- Simplify

11/2 = m <----- Divide both sides by 2

5 0

2 years ago

Read 2 more answers

Find the area of the shaded regions.

never [62]

Answer:

around 22, or 21.98

Step-by-step explanation:

$s1 = {r}^{2} \times \pi = 9 \times 3.14 = 28.26$

$s2 = 1 \times 3.14 = 3.14$

$s3 = 28.26 - (3.14 \times 2) = 28.26 - 6.28 = 21.98$

4 0

3 years ago

Graph the system of inequalities to show all possible solutions. {y<3x-2 {y ≥ -x+3

Semmy [17]

Answer:

see attachment for graph

Step-by-step explanation:

< or > : dashed line

≤ or ≥ : solid line

< or ≤ : shade below the line

> or ≥ : shade above the line

To graph the line y < 3x-2

Rewrite the equation as: y = 3x - 2

Find two points on the line:

when x = 0, y = 3(0) - 2 = -2 → (0, -2)

when x = 3, y = 3(3) - 2 = 7 → (3, 7)

Plots the found points (0, -2) and (3, 7).

Draw a straight, dashed line through the points.

To graph the line y ≥ -x + 3

Rewrite the equation as: y = -x + 3

Find two points on the line:

when x = 0, y = -(0) + 3 = 3 → (0, 3)

when x = 3, y = -(3) + 3 = 0 → (3, 0)

Plots the found points (0, 3) and (3, 0).

Draw a straight, solid line through the points.

Shade above the solid line and below the dashed line to the right of where the two lines intersect. The shaded area is the area of all possible solutions.