Gas and oil costs = $1,100.00 Repair/Maintenance = $800.00 Operating cost per mile = $0.14 Miles driven =

Mathematics

2 answers:

Greeley [361]2 years ago

8 0

Hi there

Miles driven=
(1,100+800)÷0.14
=13,571 miles

Hope it helps

zysi [14]2 years ago

8 0

Answer:

Number of miles driven by the vehicle = 13571.43 miles

Step-by-step explanation:

Cost price of the gas and oil = $1100

Amount of money spent on Repair and Maintenance of the vehicle = $800

Total amount of money spent on operating the vehicle = 1100 + 800

So, Total operating cost = 1900

Now, Operating cost per mile is given to be = $0.14

And we need to find the number of miles driven.

$\text{So, Number of miles driven by the vehicle = }\frac{1900}{0.14}$

Hence, Number of miles driven by the vehicle = 13571.43 miles

You might be interested in

Find f'(x) and state the domain of f': f(x) = In (2x^2+1)

-Dominant- [34]

Answer:

$f'(x) = \frac{4x}{2x^2+1}$

Domain: All Real Numbers

General Formulas and Concepts:

Algebra I

Domain is the set of x-values that can be inputted into function f(x)

Calculus

The derivative of a constant is equal to 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Chain Rule: $\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Derivative: $\frac{d}{dx} [ln(u)] = \frac{u'}{u}$

Step-by-step explanation:

Step 1: Define

f(x) = ln(2x² + 1)

Step 2: Differentiate

Derivative ln(u) [Chain Rule/Basic Power]: $f'(x) = \frac{1}{2x^2+1} \cdot 2 \cdot 2x^{2-1}$
Simplify: $f'(x) = \frac{1}{2x^2+1} \cdot 4x$
Multiply: $f'(x) = \frac{4x}{2x^2+1}$

Step 3: Domain

We know that we would have issues in the denominator when we have a rational expression. However, we can see that the denominator would never equal 0.

Therefore, our domain would be all real numbers.

We can also graph the differential function to analyze the domain.