(1/A) dA/dt= C where A is the population of ants and C is a constant
ln(A) = C*t + C1 where C1 is another constant that comes out of integration and t is time in days.
Plugging in: at t=0, A= 100 so C1 = ln(100) = 4.605
at t=3, A=230 so ln(230) = 3*C +4.605 so C = 0.278
Final equation:
ln(A) = 0.278t + 4.605
or:
A = exp(0.278t + 4.605)
After 14 days, A = exp(0.278*14 + 4.605) = 4875.2
Answer:
(2x+3)(5x+2)
Step-by-step explanation:
10x²+19x+6
multiply to get 60
add to get 19
10x²+19x+6
(10x²+15x)(+4x+6)
factorise:
10x²+15x
5x(2x+3)
4x+6
2(2x+3)
(2x+3)(5x+2)
Simple just do normal simple algebra:)
Answer:
f(3) ≈ 17.310
Step-by-step explanation:
e = 2.71828
Step 1: Define
f(x) = e2x - 1 + 2
x = 3
Step 2: Substitute and evaluate
f(3) = e2(3) - 1 + 2
f(3) = 6e + 1
f(3) = 16.3097 + 1
f(3) = 17.3097
f(3) ≈ 17.310
