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Marina86 [1]
3 years ago
11

In the diagram all the angles shown are right angles. The length of AB=4 and BC=5 as indicated in the diagram. What is the perim

eter of the entire figure?

Mathematics
2 answers:
Elena L [17]3 years ago
6 0
The perimeter of the entire figure would be 18.
kykrilka [37]3 years ago
3 0

Answer: choice C, 18

==============================

Explanation:

We don't know how long each little horizontal piece is, but we do know that the smaller horizontal pieces combine to fully span 5 units across. The top and bottom sides effectively are both 5 units long. Think of a rectangle. Similarly, the same happens with the vertical pieces as well. They combine to get 4.

We have a figure with a perimeter similar to a rectangle that is 4 by 5, the perimeter being 4+5+4+5 = 9+9 = 18

Alternatively, you can use the formula

P = 2*L + 2*W or P = 2*(L+W)

Plug in L = 5 and W = 4 as the length and width to get P = 18 for the perimeter

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Find x if L is between N and M, and NL = (6x - 5), LM = (2x + 3), and NM = (3x+13)?
anastassius [24]

Answer:

x = 3

Step-by-step explanation:

Here, we want to find the value of x

By mathematical convention;

NM = NL + LM

Now, substitute individual values

3x + 13 = (6x-5) + (2x + 3)

3x + 13 = 6x-5 + 2x + 3

3x + 13 = 8x -2

Collect like terms

8x -3x = 13 + 2

5x = 15

x = 15/5

x = 3

3 0
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Write and equation in slope intercept form of a line that has a slope of 1/3 and passes through the point (6,0)
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y=(1/3)x-2

Step-by-step explanation:

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hence, y-0=1/3(x-6) or y=(1/3)x-2

3 0
2 years ago
What is nine more than a number y, if that number is 4?
IceJOKER [234]

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Step-by-step explanation:

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5 0
3 years ago
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If it takes 6 hours for a plane to travel 720km with a tail wind and 8 hours to make the return trip with a head wind. Find the
denis-greek [22]

The speed of wind and plane are 105 kmph and 15 kmph respectively.

<u>Solution:</u>

Given, it takes 6 hours for a plane to travel 720 km with a tail wind and 8 hours to make the return trip with a head wind.  

We have to find the air speed of the plane and speed of the wind.

Now, let the speed wind be "a" and speed of aeroplane be "b"

And, we know that, distance = speed x time.

\text { Now, at tail wind } \rightarrow 720=(a+b) \times 6 \rightarrow a+b=\frac{720}{6} \rightarrow a+b=120 \rightarrow(1)

Now at head wind → 720=(a-b) \times 8 \rightarrow a-b=\frac{720}{8} \rightarrow a-b=90 \rightarrow(2)

So, solve (1) and (2) by addition

2a = 210

a = 105

substitute a value in (1) ⇒ 105 + b = 120

⇒ b = 120 – 105 ⇒ b = 15.

Here, relative speed of plane during tail wind is 120 kmph and during head wind is 90 kmph.

Hence, speed of wind and plane are 105 kmph and 15 kmph respectively.

6 0
3 years ago
HELP ASAPPPPPPPPP ILL MARK BRAINLIEST
pogonyaev

Answer:

the answer would be C

Step-by-step explanation:

the opposite of exponents is square root it

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