Answer:
The slope of the line that contains diagonal OE will be = -3/2
Step-by-step explanation:
We know the slope-intercept form of the line equation
y = mx+b
Where m is the slope and b is the y-intercept
Given the equation of the line that contains diagonal HM is y = 2/3 x + 7
y = 2/3 x + 7
comparing the equation with the slope-intercept form of the line equation
y = mx+b
Thus, slope = m = 2/3
- We know that the diagonals are perpendicular bisectors of each other.
As we have to determine the slope of the line that contains diagonal OE.
As the slope of the line that contains diagonal HM = 2/3
We also know that a line perpendicular to another line contains a slope that is the negative reciprocal of the slope of the other line.
Therefore, the slope of the line that contains diagonal
OE will be = -1/m = -1/(2/3) = -3/2
Hence, the slope of the line that contains diagonal OE will be = -3/2
Answer:
The value is 
Step-by-step explanation:
The diagram illustrating the question is shown on the first uploaded image
From the question we are told that
The distance from city A to B is AB = 467.3 miles
The bearing from B to C is 
The bearing from B to A is 
The bearing from A to B is 
The bearing from A to C is 
Generally from the diagram

=> 
Also

and

=> 
=> 
Generally according to Sine Rule

=>
So

=> 
Also


Generally the additional flyer miles that Adam will receive if he takes the connecting flight rather than the direct flight is mathematically represented as
![k = [CA +BC] - AB](https://tex.z-dn.net/?f=k%20%3D%20%5BCA%20%2BBC%5D%20%20-%20AB%20)
=> ![k = [260 .1 +316.8]- 467.3](https://tex.z-dn.net/?f=%20k%20%3D%20%5B260%20.1%20%2B316.8%5D-%20467.3%20)
=> 
Answer:
Option A
Step-by-step explanation:
the y value has a constant slope of 5 while the other tables have changing slopes
The speed of the current is 7 miles per
hour.
Step-by-step explanation:
Let × represent speed of the current.
We have been given that a motorboat
maintained a constant speed of 11 miles per
hour relative to the water in going 18 miles
upstream and then returning.
The speed of motorboat while going
upstream would be 11
The speed of motorboat while going
downstream would be 11 + 2
Time
Distance
Speed
<span>2 ln 8 + 3 ln y simplifies to ln 8^2 + ln y^3, which in turn simplifies to
ln 64/y^3, or ln {64*y^3}</span>