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3 years ago

Factor the algebraic expression 24q - 76u + 104i - 52b - 36i (help?)

Mathematics

2 answers:

Whitepunk [10]3 years ago

8 0

Step-by-step explanation:

24q-76u+104i-52b-36i

24q-76u-68i-52b

4(6q-19u-17i-13b)

Arada [10]3 years ago

5 0

Answer:

4(6q-19u-13b+17i)

Step-by-step explanation:

each of the variables is divisble by 4, thus allowing you to factor out 4.

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PLZ HELP ASAP!! 100 points!!! <br><br> Are these examples of direct variation? Please explain

Grace [21]

Answer:

mathematical relationship between two variables that can be expressed by an equation in which one variable is equal to a constant times the other.

8 - direct variation Since the equation can be written in the form y=kx. , y varies directly with x and k. The constant of variation, k, is 3.25

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y doesn't vary directly with x

10 - direct variation Since the equation can be written in the form y=kx, y varies directly with x and k. The constant of variation, k, is -2.4

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3 years ago

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Molly went shopping to buy jewelry. All of the pairs of earrings, e, cost $15.50 and the necklaces, n, cost $40.50. If she spend

Ostrovityanka [42]

Answer:

15.50x5+40.50x2 = $158.50

Step-by-step explanation:

She will buy 5 earrings and 2 pairs of necklaces

(15.50 x 5) + (40.50 x 2)

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3 years ago

What is point slope form used for.

egoroff_w [7]

Point slope form is an equation to graph lines.

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2 years ago

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Find all points on the x-axis that are 14 units from the point (6,-7) All points on the x-axis that are 14 units from the point

Maksim231197 [3]

Answer: $(6+7\sqrt{3},0)\text{ and }(6-7\sqrt{3},0)$ are the required points.

or (18.124,0) and ( -6.124,0) are the required points.

Step-by-step explanation:

Let (x,0) be the point on x -axis that are 14 units from the point (6,-7) .

Then by distance formula , we have

$\sqrt{(x-6)^2+(0-(-7))^2}=14\ \ \ [\ \because distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}]$

Taking square on both the sides , we get

$(x-6)^2+7^2=14^2\\\\\Rightarrow\ x^2+6^2-2(6)x+49=196\\\\\Rightarrow\ x^2+36-12x=147\\\\\Rightarrow\ x^2-12x=111\\\\\Rightarrow\ x^2-12x-111=0$

Using quadratic formula : $x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\dfrac{12\pm\sqrt{(-12)^2-4(1)(-111)}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{144+444}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{588}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{2^2\times7^2\times3}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm14\sqrt{3}}{2}\\\\\Rightarrow\ x=6\pm7\sqrt{3}$