For the first question, we can extend all of the lines on the trapezoid, and triple the distance from B on the line, so we can use the fact that B is (2, 2), A is (0, 0), C is (4, 2), and D is (6, 0) to get that the new coordinates are A (-4, -4), B (2, 2), C (8, 2), and D (14, -4).
For the second question, notice that we are changing the size on the same line, and every side length is tripled by 3. If every side length is tripled by 3, then the perimeter of the new image is triple the perimeter of the original.
Answer:
SAS stands for "side, angle, side" and means that we have two triangles where we know two sides and the included angle are equal. If two sides and the included angle of one triangle are equal to the corresponding sides and angle of another triangle, the triangles are congruent.
Step-by-step explanation:
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Answer:
x -y = -5
3x +y = -11
Step-by-step explanation:
We assume you want two linear equations. Since you know a point on each line, the only thing you need to choose is the slope of the two lines through that point. We can make the slopes be +1 and -3, for example. Then the point-slope equations are ...
y -k = m(x -h) . . . . . . line with slope m through point (h, k)
y -1 = +1(x +4)
y -1 = -3(x +4)
We can use these equations "as is", or put them in whatever form you like. I personally prefer "standard form:" ax+by=c.
<u>First equation</u>:
y -1 = x +4 . . . . . . eliminate parentheses
-5 = x -y . . . . . . . keep positive x term, put x and y together, separate from the constant
x - y = -5 . . . . . . standard form
<u>Second equation</u>:
y -1 = -3x -12 . . . . eliminate parentheses
3x +y = -11 . . . . . . add 3x+1 to both sides
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A system of equations with solution (-4, 1) is ...