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VashaNatasha [74]
3 years ago
7

Three bands and two comics are perforing for a student talent show how many different programs

Mathematics
1 answer:
aliina [53]3 years ago
8 0
Two. (bands) and (comics)
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Which set of three angles could represent the interior angles of a triangle?
timofeeve [1]
C would be the correct answer
7 0
3 years ago
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For the function f(t) =Pe^rt , if P= 7 and r= 0.07 then what is the value of f(7) to the nearest tenth?
White raven [17]

Answer:

A. 11.4  

Step-by-step explanation:

f(t) = P e^{rt}

Data:

P = 7

r = 0.07

Calculation:

\begin{array}{rcl}f(t) & = &Pe^{rt}\\f(7)& = & 7 e^{(0.07 \times 7)}\\ & = & 7 e^{0.49}\\& \approx & 7 \times 1.632\\ & \approx & \mathbf{11.4}\\\end{array}

8 0
3 years ago
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1/4 of the players on every team are girls. Write 3 fractions equivalent to 1/4
Andrew [12]

Answer:

2/8, 3/12 and 4/16

Step-by-step explaination:

All these fractions are equivalent to 1/4 as the numerator is a multiple of 1, the denominator is a multiple of 4, and the numerators are all a quarter of their respective denominators.

6 0
2 years ago
Solve the equation for theta (0°≤theta&lt;360°)<br><br>2 sin theta = 1​
Oduvanchick [21]

Answer:

30 degrees

Step-by-step explanation:

To figure out theta is using a bit of simple trigonometry.

2sin(theta) = 1

= sin(theta) = 0.5

Using arcsin (sin^-1) we can isolate x

x = arcsin(0.5)

x = 30

4 0
2 years ago
The number of phone calls that Actuary Ben receives each day has a Poisson distribution with mean 0.1 during each weekday and me
Dovator [93]

Answer:

There is a 0.73% probability that Ben receives a total of 2 phone calls in a week.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

The problem states that:

The number of phone calls that Actuary Ben receives each day has a Poisson distribution with mean 0.1 during each weekday and mean 0.2 each day during the weekend.

To find the mean during the time interval, we have to find the weighed mean of calls he receives per day.

There are 5 weekdays, with a mean of 0.1 calls per day.

The weekend is 2 days long, with a mean of 0.2 calls per day.

So:

\mu = \frac{5(0.1) + 2(0.2)}{7} = 0.1286

If today is Monday, what is the probability that Ben receives a total of 2 phone calls in a week?

This is P(X = 2). So:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 2) = \frac{e^{-0.1286}*0.1286^{2}}{(2)!} = 0.0073

There is a 0.73% probability that Ben receives a total of 2 phone calls in a week.

3 0
3 years ago
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